Hey there, Lets solve this one by one
Firstly, a<span>dd </span>11<span> to both sides
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Now, </span><span>Simplify </span><span>5+11</span><span> to </span><span>16
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Finally, d</span><span>ivide both sides by variable </span><span>y
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Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be: 
miles/hour
and the <u>speed of Pratap against the current</u> will be: 
miles/hour.
Suppose, the rate of Pratap in still water is 
and the rate of current is 
.
So, the equations will be........
Adding equation (1) and (2) , we will get......
Now, plugging this 
into equation (1), we will get.....
Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Answer:
308
Step-by-step explanation:
Answer:
40%
Step-by-step explanation:
i used a calculator
Answer:
6^ -24
Step-by-step explanation:
We know that a^b^c = a^ (b*c)
(6^-4)^6 = 6^ (-4*6) = 6^ -24
