Question

Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose 1st term is 4. BRANLIEST ASAP TY!!!​

Answer 1

Step-by-step explanation:

Nth term of a G. P. is given as:

$t_n=ar^{n-1} \\ \\ \therefore \: t_{10}=4 \times ( \frac{3}{2} )^{10-1} \\ \\ \therefore \: t_{10}=4 \times ( \frac{3}{2} )^{9}\\ \\ \therefore \: t_{10}=4 \times \frac{3^{9}}{2^{9}} \\ \\ \therefore \: t_{10}= \frac{3^{9}}{2^{7}} \\ \\ \therefore \: t_{10}= \frac{19,683}{128} \\ \\ \therefore \: t_{10}=153.773438$