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Kitty [74]
4 years ago
7

How much greater is (2^3)^2 than 2^3 x 2^2

Mathematics
2 answers:
Elena L [17]4 years ago
6 0

Answer:

(2^3)^2/2^3X2^2 = 6/4 = 3/2

Step-by-step explanation:

(2^3)^2 = 6^2 = 36

2^3 X 2^2 = 6 X 4 = 24

Svetlanka [38]4 years ago
5 0

Answer:

(2^3)^2 is 32 greater than 2^3 * 2^2

Step-by-step explanation:

(2^3)^2 = 2^(3 * 2) = 2^6 = 64

2^3 * 2^2 = 8 * 4 = 32

Difference:

64 - 32 = 32

Answer: (2^3)^2 is 32 greater than 2^3 * 2^2

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Sum and difference tan(135+30)
Mumz [18]
\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\sin y\cos x}{\cos x\cos y-\sin x\sin y}=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

So,

\tan(135^\circ+30^\circ)=\dfrac{\tan135^\circ+\tan30^\circ}{1-\tan135^\circ\tan30^\circ}

You should know that \tan135^\circ=-1 and \tan30^\circ=\dfrac1{\sqrt3}

Putting everything together,

\tan(135^\circ+30^\circ)=\dfrac{-1+\dfrac1{\sqrt3}}{1-(-1)\left(\dfrac1{\sqrt3}\right)}=\dfrac{1-\sqrt3}{\sqrt3+1}=\sqrt3-2
7 0
4 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles are used.
Sati [7]

Answer:

a) aₙ = 4.(2)^n-1

b) aₙ = 2+3(n-1)

c) aₙ = 3+4(n-1)

d) aₙ = 3.(4)^n-1

Step-by-step explanation:

a) a geometric sequence with first term of 4 and a common ratio of 2

aₙ = ar^n-1

where a is the first term and r is the common ratio

aₙ = 4.(2)^n-1

Comparing with the standard form:

1st term = 4

Common ratio = 2

b) an arithmetic sequence with a first term of 2 and a common difference of 3

The standard form of arithmetic sequence is:

aₙ = a₁ + d(n-1)

where a₁ is the first term and d is the common difference

Given: aₙ = 2+3(n-1)

Comparing with standard equation

First term = 2

Common difference = 3

c) an arithmetic sequence with a first term of 3 and a common difference of 4

The standard form of arithmetic sequence is:

aₙ = a₁ + d(n-1)

where a₁ is the first term and d is the common difference

Given: aₙ = 3+4(n-1)

Comparing with standard equation

First term = 2

Common difference = 3

d) a geometric sequence with first term of 3 and a common ratio of 4

aₙ = ar^n-1

where a is the first term and r is the common ratio

aₙ = 3.(4)^n-1

Comparing with the standard form:

1st term = 3

Common ratio = 4

6 0
4 years ago
Do the ratios 6:3 and 8:4 form a proportion?
Serhud [2]

Answer:

yes

Step-by-step explanation:

6:3 and 8:4

6:3

Divide by 3

6/3: 3/3

2:1

8:4

Divide by 4

8/4: 4/4

2:1

They are the same so they form a proportion

6 0
3 years ago
Solve the systems by the addition method: {x-2y = -4 2x + y = 7
Klio2033 [76]

Answer:

(2, 3 )

Step-by-step explanation:

Given the 2 equations

x - 2y = - 4 → (1)

2x + y = 7 → (2)

Multiplying (2) by 2 and adding to (1) will eliminate the y- term

4x + 2y = 14 → (3)

Add (1) and (3) term by term to eliminate y, that is

5x = 10 ( divide both sides by 5 )

x = 2

Substitute x = 2 into either of the 2 equations and evaluate for y

Substituting into (2)

2(2) + y = 7

4 + y = 7 ( subtract 4 from both sides )

y = 3

Solution is (2, 3 )

4 0
4 years ago
Juliana bought a pack of stickers There are 15 stickers in the pack, and 8/10 of the stickers are hearts. How many stickersin th
irga5000 [103]
12. You do 8/10 times x/15, you multiply 15 times 8 which equals 120 then divide by 10
3 0
3 years ago
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