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Papessa [141]
3 years ago
10

The mass of a small virus is 10^-20 kg. The mass of an average human cell is 10^-12 kg. Which of the two has lesser mass? how ma

ny less is it?
Mathematics
2 answers:
fredd [130]3 years ago
5 0

For this case we have:

10 ^ {- 20}, we must run the decimal point 20 spaces to the left.

0.00000000000000000010 \ kg

10 ^ {- 12}, we must run the decimal point 12 spaces to the left.

0.000000000010 \ kg

Thus, it is observed that the mass of a small virus is smaller!

We subtract and obtain:

10 ^ {-11}

ANswer:

The mass of a small virus is less!

Bess [88]3 years ago
5 0

Answer: -10kg

Step-by-step explanation:

10-20 =-10

10-22 =-12

-10 is lesser

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How do I factor: x to the third minus 3x squared plus 4x minus 2
Nataliya [291]

Answer:

(x² − 2x + 2) (x − 1)

Step-by-step explanation:

Use grouping.

x³ − 3x² + 4x − 2

x³ − 3x² + 2x + 2x − 2

x (x² − 3x + 2) + 2 (x − 1)

x (x − 2) (x − 1) + 2 (x − 1)

(x (x − 2) + 2) (x − 1)

(x² − 2x + 2) (x − 1)

7 0
3 years ago
Read 2 more answers
4n^(2)+4n=3<br> Please help with the work
Kaylis [27]

Answer:

n= 1/2 ( \frac{1}{2} )  or  (0.5)

AND

n= -3/2 ( -\frac{3}{2} ) or (-1.5)

Step-by-step explanation:

4n^2+4n=3

step1: move 3 to the other side and make the equation equal to zero.

4n^2+4n-3=0

step2: factorise the equation.

(2n-1)(2n+3)=0

step3: make each bracket equal to zero.

2n-1=0

2n+3=0

step4: solve for n values.

<u>1.</u> 2n-1=0

(add 1 for both sides)

2n=1

(divide by 2 for both sides)

n= 1/2 ( \frac{1}{2} )  or  (0.5)

<u>2.</u> 2n+3=0

( subtract 3 for both sides)

2n=-3

(divide by 2 for both sides)

n= -3/2 ( -\frac{3}{2} ) or (-1.5)

3 0
3 years ago
Question
dem82 [27]

Answer:

AABC and AXYZ are similar triangles. The lengths of two sides of each triangle are shown. Find the lengths of the third side of each triangle

7 0
2 years ago
The list shows the numbers of each type of pie baked at a bakery today.
Alenkasestr [34]
35%, because the apple pies account for 65% of the pies made
4 0
3 years ago
one days discharge at its mouth, 3 trillion gallons, could supply all of country A’s household for 5 months. how much water an a
serious [3.7K]

let's use engineering notation for the sake of brevity.

1 trillion is 1,000,000,000,000, or just 1E12, twelve zeros.

1 million is then 1E6, six zeros.

we know the discharge for one day is 3E12 gallons, and that'd do just fine for country A for 5 months.  How many gallons in 1 month only?

\bf \begin{array}{ccll} gallons&months\\ \cline{1-2} 3E12&5\\ x&1 \end{array}\implies \cfrac{3E12}{x}=\cfrac{5}{1}\implies 3E12=5x \\\\\\ \cfrac{3E12}{5}=x\implies 6E11=x\implies 600000000000=x

if there are 200million inhabitants in A, namely 200E6 or 2E8 inhabitants, how many gallons per inhabitant from all those 6E11 gallons?

\bf \begin{array}{ccll} gallons&households\\ \cline{1-2} 6E11&2E8\\ x&1 \end{array}\implies \cfrac{6E11}{x}=\cfrac{2E8}{1}\implies 6E11=2E8x \\\\\\ \cfrac{6E11}{2E8}=x\implies \cfrac{600000000000}{200000000}=x\implies 3000=x

5 0
3 years ago
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