1. 2. 3. 4. pls answer

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

4 0

Answer:

First clear your question please.

Step-by-step explanation:

You might be interested in

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

According to this property, x + 0 = x.

Mumz [18]

The identity property of addition states that the sum of any number and 0 is the original number.

so...x + 0 = x would be the identity property of addition (also called the additive identity)

3 0

3 years ago

Read 2 more answers

After six weeks of the coupon offer, the owner of the restaurant needs to decide if the restaurant should continue to run

sladkih [1.3K]

I’m just here so I can ask a questin

7 0

3 years ago

Please solve the equation _4(4n+2)=4

MrRissso [65]

16n+8=4
16n=4-8
16n=-4
n=-4/16
n=-1/4.

8 0