Question

Find the distance between (-5,-6) and (-3,-8 WILL GIVEBRANLIEST TO FIRST PERSON WHO AWNSES WITH EXPLANATION

Answer 1

Answer:

d = √8

d ≈ 2.82843

Step-by-step explanation:

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in our coordinates into the distance formula:

$d = \sqrt{(-3 + 5)^2+(-8 + 6)^2}$

$d = \sqrt{(2)^2+(-2)^2}$

$d = \sqrt{4+4}$

$d = \sqrt{8}$

To find the decimal, simply evaluate the square root:

√8 = 2.82843

Answer 2

Answer:

$\boxed{2 \sqrt{2} \: \: units}$

Step-by-step explanation:

Let the points be A and B

A ( - 5 , - 6 ) ⇒ ( x₁ , y₁ )

B ( -3 , - 8 )⇒( x₂ , y₂ )

Now, let's find the distance between these two points:

AB = $\mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }$

Plug the values

⇒$\mathsf{ \sqrt{( - 3 - ( - 5) )^{2} + {( - 8 - ( - 6))}^{2} } }$

When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression

⇒$\mathsf{ \sqrt{ {( - 3 + 5)}^{2} + {( - 8 + 6)}^{2} } }$

Calculate

⇒$\mathsf{ \sqrt{ {(2)}^{2} + {( - 2)}^{2} } }$

Evaluate the power

⇒$\mathsf{ \sqrt{4 + 4} }$

Add the numbers

⇒$\mathsf{\sqrt{8} }$

Simplify the radical expression

⇒$\mathsf{ \sqrt{2 \times 2 \times 2}}$

⇒$\mathsf{2 \sqrt{2} }$ units

Hope I helped!

Best regards!