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lesantik [10]
2 years ago
8

At the market, 7 oranges cost $4.55. How much do 10 oranges cost?

Mathematics
2 answers:
lbvjy [14]2 years ago
8 0

it's 6.50 because when you divide 4.55/7 it's 0.65 multiplied by 10 it's 6.50

masha68 [24]2 years ago
7 0

Answer: $6.50

Step-by-step explanation:

First you do 4.55/7 and you get 0.65, then you multiply that by 10 which will get you $6.50.

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3 years ago
Solve using substitution y=x-3 4x+y=32
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3 years ago
Four times a number minus twice another number is -8. The sum of the two number is 19.Find the numbers
grigory [225]
1. To solve this exercise, you must make a system of equations.

 2. You have that f<span>our times a number minus twice another number is -8:
</span>
 4x-2y=-8

 3. And t<span>he sum of the two number is 19:
</span>
 x+y=19

 4. As you can see, you have two equations:

 4x-2y=-8   (i)
 x+y=19     (ii)

 5. Let's clear the "x" from the equation (ii):

 x=19-y

 6. Now, you need to susbtitute x=19-y into the equation (i):

 4x-2y=-8
 4(19-y)-2y=-8
 76-4y-2y=-8
 76-6y=-8
 -6y=-8-76
 -6y=-84
 y=-84/-6
 y=14

 7. You must susbstitute y=14 into the equation (ii) and clear "x":

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6 0
3 years ago
English
asambeis [7]

Answer:

38.25 units.

Step-by-step explanation:

The trapezoid is given with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)

When given vertices ( x1, y1), (x2, y2)

We use the formula:

√(x2 - x1)² + (y2 - y1)² to find the length of the sides of the Trapezoid

Side QR: Q(8, 8), R(14, 16)

= √(x2 - x1)² + (y2 - y1)²

= √(14 - 8)² + (16 - 8)²

= √6² + 8²

= √36 + 64

= √100

= 10 units

Side RS: R(14, 16), S(20, 16)

= √(x2 - x1)² + (y2 - y1)²

= √(20 - 14)² + (16 - 16)²

= √6² + 0²

= √36

= 6 units

Side ST : S(20, 16), T(22, 8)

= √(x2 - x1)² + (y2 - y1)²

= √(22 - 20)² + ( 8 - 16)²

= √2² + (-8)²

= √4 + 64

= √68

= 8.2462112512

≈ nearest hundredth = 8.25 units

Side QT, Q(8, 8), T(22, 8)

= √(x2 - x1)² + (y2 - y1)²

= √(22 - 8)² + (8 - 8)²

= √14² + 0²

= √196

= 14 units

The Perimeter of a Trapezoid is the sum of all it's sides.

P = QR + RS + ST + QT

P = (10 + 6 + 14 + 8.25) units

P = 38.25 units

Therefore, the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8) is 38.25units.

3 0
3 years ago
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Lelu [443]

Step-by-step explanation:

{x}^{2}  +  {16} \\  {x}^{2}  +  {4}^{2}  \\(x + 4 {)}^{2}  \\  =  {x}^{2}  + 8x + 16

5 0
3 years ago
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