Answer:sry I don’t get tht type of math if I did I would of helped u sry :( but I hope u have a wonderful Christmas break ❄️
Step-by-step explanation:
Answer:
Original function:
f(x) = log2(x)
Transformed function:
f(x) = -log2(x - 1) + 2
The transformation process is to take f(x)=log2(x) and shift it to the right 1 unit and shift 2 units up. Then flip it down.
A log cannot have a negative value for an argument. Set the argument greater than zero.
x - 1 > 0
x > 1
The domain is all values greater than 1.
To find the range, use the domain.
Evaluate f(1.00001), f(2) , f(200), and f(2000)
Then use those values to determine the range.
Answer:
dh/dt = 0.4 m/min
Step-by-step explanation:
The volume of the cone is:
V(c) = (1/3)*r² *h if always h = 3r then r = h/3
The volume of the cone as a function of h will be:
V(h) = (1/3)* (h/3)²*h
V(h) = (1/27)*h³
The increasing rate of the volume is equal to the rate of sand added the:
D(V)/dt = (1/27)*3*h²*dh/dt
D(v) / dt = 10 m³/min
h = 15 m and dh/dt is the rate of increasing of the height
By substitution
10 m³/min = ( 1/9)* 225 * dh/dt (m²)
dh/dt = 90 / 225 m/min
dh/dt = 0.4 m/min
Answer:
B. There is not sufficient evidence at the 0.02 level of significance that the new technique reduces training time.
Step-by-step explanation:
We are given that using traditional methods it takes 107 hours to receive an advanced flying license.
A researcher believes the new technique may reduce training time and decides to perform a hypothesis test.
Let 
= <u><em>average training time to receive an advanced flying license</em></u>
So, Null hypothesis, 
: 
107 hours {means that the new technique doesn't reduce training time}
Alternate Hypothesis, 
: < 107 hours {means that the new technique may reduce training time}
Now, it is stated that after performing the test on 50 students, the researcher decides to reject the null hypothesis at a 0.10 level of significance.
As we know that if the test statistics value is rejected at a 10% level of significance, then it must not be rejected at the 0.02 level of significance.
This means that there is not sufficient evidence at the 0.02 level of significance that the new technique reduces training time because our null hypothesis has not been rejected.
The greatest common factor for 10x and 2 is so we take out 2 to give:_
2(5x + 1)
Its D
