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melisa1 [442]
3 years ago
10

Three people play a game on each spinner in the previos problem.

Mathematics
1 answer:
arlik [135]3 years ago
5 0

Answer:

Step-by-step explanation:

All other things being equal, spinner A is fine. It is a fair spinner.

Spinner B is not fair. Players 1 and 3 have only 1 number each. Player 2 on the other hand, has 2 numbers that work for him. If player 2 puts in two dollars and players 1 and 3 one dollar each, that should even up the odds. Now you want it just to be fair. So I think player 2 has to put up 2 dollars and players 1 and 3 each put up one. The pot is 4 dollars each time it is played.

Spinner 3 is not fair either. Player one has 2 chances. Player 2 has 3 chances and player 3 has but one chance. There are 6 chances in all. Player 1 should put up 2 dollars to play player 1 should put up 3 dollars and player 1 should put up 1 dollar.

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Find the value of x when : 2^30/8^9=2^x
artcher [175]

Answer:

x = -3

Step-by-step explanation:

Okay, the first thing to do is get that 8 away from the fraction. How can we do it? When you have 2³ you have 8, is the same thing, so let's do it:

2³⁰/(2³)⁹ = 2^x

When you have a number with the shape (a^x)^y, you can write it as a^(x•y), so:

(2³)⁹ = 2^3•9 = 2²⁷

Now we have:

2³⁰/2²⁷ = 2^x

When you have a division like this: (a^x)/(a^y), you can write it as a^(x-y), so:

2^(30-27) = 2^x

2^-3 = 2^x

Now you know that x = -3

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