The tangent to
at the point (0, 5) has a slope equal to the derivative evaluated at
.

This tangent passes through the point (0, 5), so its equation is

The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is

Answer:
I believe your answer is 24
Step-by-step explanation:24/1
Answer: 4th option
Explanation:
I added a picture so please check it
F because the other answers are way to high