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AURORKA [14]
3 years ago
9

You have performed a serial dilution of an unknown sample and counted 73 CFU on a countable plate that was marked as a 10^-4 dil

ution and you used a 0-.1 mL to inoculate the plate. What is the population density of the original sample?
Chemistry
1 answer:
dexar [7]3 years ago
4 0

Hey there!:

To find the original sample population density, divide the conted colonies by the dilution factor and the inoculate:

= 73 / (10⁻⁴ * 0.1)

= 73*10⁵

Thus, the original sample's population density was 7.3*10⁶ or 73* 10⁵.

Hope this helps!

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Answer:

This is False

Explanation:

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3 years ago
The pH of a 0.78M solution of 4-pyridinecarboxylic acid HC6H4NO2is measured to be 2.53.Calculate the acid dissociation constant
nika2105 [10]

Answer : The value of acid dissociation constant is, 1.1\times 10^{-5}

Solution :  Given,

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pH = 2.53

First we have to calculate the hydrogen ion concentration.

pH=-\log [H^+]

2.53=-\log [H^+]

[H^+]=2.95\times 106{-3}M

Now we have to calculate the acid dissociation constant.

The equilibrium reaction for dissociation of (weak acid) is,

                        HC_6H_4NO_2\rightleftharpoons C_6H_4NO_2^-+H^+

initially conc.         0.78                0             0

At eqm.               (0.78-x)              x             x  

The expression of acid dissociation constant for acid is:

k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}

As, [H^+]=[C_6H_4NO_2^-]=x

So,  x=2.95\times 106{-3}M

Now put all the given values in this formula ,we get:

k_a=\frac{(x)\times (x)}{(0.78-x)}

k_a=\frac{(2.95\times 106{-3})\times (2.95\times 106{-3})}{(0.78-2.95\times 106{-3})}

K_a=1.1\times 10^{-5}

Therefore, the value of acid dissociation constant is, 1.1\times 10^{-5}

7 0
4 years ago
What is the formula for the covalent compounds sulfur pentaoxide and hydrogen monobromide?
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7 0
3 years ago
Complete the balanced molecular chemical equation for the reaction below.
Alenkasestr [34]

Answer:

Following are the complete balance of the given equation:

Explanation:

Given equation:

Cu_2SO_4(aq) + Li_3PO_4(aq)

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