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gayaneshka [121]
3 years ago
7

What are the roots of x in -10x^2+12x-9=0​

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

- 10 {x}^{2}  + 12x - 9 = 0 \\ \Leftrightarrow {x}^{2}  -  \frac{6}{5} x +  \frac{9}{10 }  = 0 \\ \Leftrightarrow  {x}^{2}  -  \frac{6}{5}x +  \frac{9}{25}  =  -  \frac{9}{10}  +  \frac{9}{25}  \\ \Leftrightarrow   \underbrace{ {(x -  \frac{3}{5} )}^{2} }_{ \geqslant 0} =  -  \frac{27}{50}  \\ \Leftrightarrow x\in\emptyset \\ \Rightarrow Roots: None

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Step-by-step explanation:

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Let say; By y(x)= y(e)  

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