This test is literally the death of me but can anyone help?
2 answers:
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Answer:
Step-by-step explanation:
Given the mass is m =16kg, and 1N force will stretch the spring 1 m.
That is, F =1N,Z =1m. Now find the spring constant k:
F = kL = 1 = k(1) = k= 1N/m.
The damping force is 8times the instantaneous velocity, this means β = 8,
and the external force is f(t) = 0
Initially the object compressed 0.6m above equilibrium position,
with the downward velocity is 2m/s.
The differential equation for a spring mass system with
damping force and extemal force is: mx" + βxt + kx = f(t).
so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.
Now solve the DE:
The auxilary equation for the homogeneous equation is 16x"+8x'+x=0
solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.
Then the general solution for the homogenous system is: .
Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:
.
Hence, .
The population size after 6 years and after 8 years are 147 and 169 population respectively
<h3>Exponential functions</h3>The standard exponential function is expressed as y = ab^x
where
a is the base
x is the exponent
Given the function that represents the population size P (t) of the species as shown;
For the population size after 6 years
For the population after 8 years
Hence the population size after 6 years and after 8 years are 147 and 169 population respectively
Learn more on exponential function here: brainly.com/question/2456547
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