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kotegsom [21]
3 years ago
8

Chris bought 7 packs of gum. How many pieces total

Mathematics
1 answer:
wolverine [178]3 years ago
6 0

Answer:

homie... how much gum is in one pack?

Step-by-step explanation:

12 pack = 91 gum

16 pack = 112 gum

24 pack = 168 gum

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Please help me !!!!!!
cestrela7 [59]

Given:

The set of pair and graphs.

To find:

The domain and range.

Solution:

We know that,

Domain is the set of x-values or input values.

Range is the set of y-values or output values.

(a)

The given set of ordered pairs is

{(-3,3),(5,5),(-3,2),(5,3)}

Here, the x-coordinates are -3, 5, -3, 5.

A set contains distinct values.

Therefore, the domain is {-3,5}.

(b)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,1),(-1,0.5),(-1,3),(0,0),(0,2),(1,0.5),(1,3)(2,1)}

Here, the y-values are 1, 0.5, 3, 0, 2, 0.5, 3, 1.

Therefore, the range is {0, 0.5, 1, 2, 3}.

(c)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,3),(-1,3),(0,1),(2,4)}

Here, the x-values are -2, -1,0, 2.

Therefore, the domain is {-2,-1,0,2}.

4 0
3 years ago
He first three terms of a geometric sequence are as follows. 10 , 30 , 90 find the next two terms of this sequence.+
ankoles [38]
10*3=30
30*3=90
90*3=270
270*3=810

or

10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810

the next two terms of this sequence are 270 and 810.
4 0
3 years ago
1. Taylor needs to purchase a car. The car Taylor plans to purchase costs $10,000. Taylor has saved $2,000 to use as a down paym
Alexxandr [17]

Answer:

a. The amount Taylor will need to finance is $8,000

b. The amount Taylor pays as interest in one year is $400

Step-by-step explanation:

The given parameters of the financing for the car are;

The cost of the car Taylor plans to purchase, C = $10,000

The amount Taylor has saved to be used as down payment, S = $2,000

The interest rate of the credit Taylor is offered = 5%

The duration given for repayment of the loan = 5 years

a. To purchase the car, the amount Taylor will need to finance, 'P', is given as follows;

P = C - S

∴ P = $10,000 - $2,000 = $8,000

b. The amount of interest on the loan in one year, 'I', is given by the following formula;

I = \dfrac{P \times R \times T}{100}

Where;

I = The interest payed

P = The principal amount taken as loan = $8,000

R = The interest rate = 5% APR

T = The time period the interest is applied = 1 year

Plugging in the values, we get;

I = \dfrac{\$ \, 8,000 \times 5 \times 1}{100} = \$ \, 400

The interest Taylor will pay on the loan in one year, I = $4,00

7 0
3 years ago
Can u solve these 4 me?
Ber [7]

So for this:

(-1/3+-0.3/3+1) ^2

(-1/3-0.1+1)^2

(1-1.3/3)^2

(1-0.433333)^2

0.566667^2

Answer: 0.321111

0.32

8 0
3 years ago
7.22 (10b-3) =7b-14
faust18 [17]
Multiply 7.22 onto 10b and -3
new equation - 72.2b-21.66=7b-14

add 21.66 onto -14
new equation - 72.2b=7b+7.66

subtract 7b from 72.2
new equation: 65.2b=7.66

divide 65.2 from b
new equation: b=7.66/65.2

final answer: b=0.117
3 0
4 years ago
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