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3 years ago

8

I have a math test coming up can people help me?!?!?!

2 answers:

kogti [31]3 years ago

5 0

i can help if you want

kow [346]3 years ago

4 0

Answer:

If u want sure

Step-by-step explanation:

You might be interested in

Describe the slope of the line<br> Find the slope

Dmitry_Shevchenko [17]

Answer:

Question one: Zero slope
Question two: $m=\frac{0}{4}$

Step-by-step explanation:

Given the following questions:

<u>Question one:

</u>The following line is what you call a "zero slope." Zero slopes are lines that are neither decreasing or increasing and remain at a constant or just a straight line.

Question two:

Point A = (-2, -3) = (x1, y1)
Point B = (2, -3) = (x2, y2)

Using the formula for slope or rise over run we will solve and find the slope of this line.

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{-3--3}{2--2} =\frac{0}{4}$
$m=\frac{0}{4}$

The slope of this line is "0/4."

Hope this helps.

8 0

2 years ago

Julie is 3 years older than her sister. Julie's age is 11 years old.<br> How old is her sister?

Ne4ueva [31]

Answer:

14 :)

Step-by-step explanation:

4 0

3 years ago

What is the surface area of the cylinder with height 2 yd and radius 3 yd? Round your answer to the nearest thousandth.

olasank [31]

<h2>Given :</h2>

height (h) = 2 yd

radius (r) = 3 yd

<h2>Solution :</h2>

$\boxed{ \mathrm{Surface \: Area = 2\pi r(h +r )}}$

$2 \times 3.14 \times 3 \times (3 + 2)$

$18.84 \times 5$

$\boxed{\mathrm{94.2 \: yd {}^{2} }}$

_____________________________

$\mathrm{ \#TeeNForeveR}$

3 0

3 years ago

What is the product of (a-5) and (a+3)

abruzzese [7]

= (a-5).(a+3) = a²+3a-5a-15 = a²-2a-15

3 0

3 years ago

Select all the correct answers.

Vlad1618 [11]

Answer:

The measure of reference angle is $30^{\circ}$ .
$\cos \theta=\frac{\sqrt{3}}{2}$

Step-by-step explanation:

Converting $\theta$ to degrees,

$\theta=\left(\frac{11\pi}{6} \right) \left(\frac{180}{\pi} \right)=330^{\circ}$

This means $\theta$ lies in Quadrant 4, and thus its reference angle is $360^{\circ}-330^{\circ}=\boxed{30^{\circ}}$

Since $\theta$ lies in the fourth quadrant, $\sin \theta$ and $\tan \theta$ are negative.

Since $\theta$ lies in the fourth quadrant, $\cos \theta$ is positive, and is equal to $\cos (30^{\circ})=\boxed{\frac{\sqrt{3}}{2}}$

3 0

2 years ago