Answer:
Solution given:
The volume of two similar solids are 128 m³
and 250 m³.
surface area of larger solid is 250m²
<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>
<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>
x=128
the surface are of the
smaller solid is 128m²
The answer is either c or d. I would go with answer c though. sorry if it is wrong
Answer:
-5/13
Step-by-step explanation:
sin theta = opp / hyp
sin theta = -12 /13
we can find the adj side by using the pythagorean theorem
adj^2 + opp ^2 = hyp^2
adj^2 +(-12)^2 = 13^2
adj^2 +144 =169
adj^2 = 169-144
adj^2 = 25
Taking the square root of each side
adj = ±5
We know that it has to be negative since it is in the third quad
adj = -5
cos theta = adj / hyp
cos theta = -5/13
It is biggest to smallest I presume
The population is growing unchecked
