3 years ago

How do i do this one???

Mathematics

1 answer:

Alika [10]3 years ago

8 0

2 lb and 10 oz because there are 16 ounces in an lb.

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Solve the system of equations below by graphing both equations with a

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Your answer would be c

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3 years ago

Which statement best describes how to determine whether f(x) = x2 – x + 8 is an even function? Determine whether –x2 – (–x) + 8

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Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

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3 years ago

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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3 years ago

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Anna35 [415]

The answer of 9/10 divided by 1/5 is 4.5

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3 years ago

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Answer:

Sarah is 4 ft tall.

Step-by-step explanation:

231÷84= 2.75

11 ft ÷ 2.75 = <u>4 ft</u>

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