Answer:
(A) 0.0244
(B) 1 (not 1.47 as is calculated) since probability values are between 0 and 1; 0 and 1 inclusive
Step-by-step explanation:
The rare mutation only occurs in 1 generation, out of every 2048 generations. This implies that the next occurrence will fall in or within the next 2048 generations (2 generations in 4096 generations, will have the rare mutation).
(A) The probability of occurrence of this mutation at least once (at most infinity) in 50 generations of fruit flies will surely be less than, as 50 is less than 2048.
The accurate probability is gotten when 50 is divided by 2048
50÷2048 = 0.0244
(B) The probability of seeing this mutation at least once (at most infinity) in 3000 generations would have been 1.47 but for 3 reasons;
- The full question already tells that the mutation will occur once in every 2048 generations and 3000 is greater than 2048, hence there will be a sure occurrence within 3000 generations.
- Question (b) asks you to calculate the probability of seeing this mutation at least once in 3000 generations so, the probability is 1 (representing full probability).
- In probability theory or statistics, all probability values fall within 0 and 1; with 0 representing no occurrence at all and 1 representing full occurrence.
Let the required no. be x then according to question
(84/100)*x = 21
x = 21*(100/84)
x = 2100/84
x = 25
hence the required no. is 25
hope it helped
Answer:
The function is y = 40 * 2^(x/2)
The graph is in the image attached
Step-by-step explanation:
The function that models this growth is an exponencial function, that can be described with the following equation:
y = a * b^(x/n)
Where a is the inicial value, b is the rate of growth, x is the time and n is the relation between the time and the rate (the rate occurs for every two hours, so n = 2).
Then, using a = 40, r = 2 and n = 2, we have:
y = 40 * 2^(x/2)
If we plot this function, we have the graph shown in the image attached,
It is an exponencial graph, where the value of y increases very fast in relation to the increase of x.
