Answer: thank you
Step-by-step explanation:
abacnxBZCNxbnxv xzcbvxzc
Fill in the blanks to show the product number 1X2
Answer:
true
Step-by-step explanation:
2log2 6- log2 9+ 1/3log2 27 =
= log2 6² - log2 9 + log2 27^(1/3)
= log2 36 - log2 9 + log2 3
= log2 [(36 × 3)/9]
= log2 12
The statement is true.
Answer:
$11,130.47
Step-by-step explanation:
The amortization formula can be used. It tells you the monthly payment amount A for some principal P, interest rate r, and n payments.
A = P(r/12)/(1 -(1 +r/12)^(-n))
Filling in your values, we get ...
200 = P(.03/12)/(1 -(1 +.03/12)^-60) = P(.0025)/(1 -1.0025^-60)
P = 200(1 -1.0025^-60)/.0025 ≈ 200×55.6523577
P ≈ 11,130.47
The present value of the loan is $11,130.47.
Answer:
34
first of all use formula:
n(AUB)=n(A)+n(B)-n(AnB)
