Answer:
Therefore the ball strikes the ground 5.98 s after kick.
Step-by-step explanation:
Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation 
where h is height in feet and t is time in second.
When the ball touches the ground then the height will be zero.
i.e h(t)=0
Therefore
Since -2≠0 then 
[The solution of a quadratic equation ax²+bx+c=0 is
here a=8, b=-32 and c=-95]
![\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}](https://tex.z-dn.net/?f=%5CRightarrow%20t%20%3D%5Cfrac%7B-%28-32%29%5Cpm%5Csqrt%7B%28-32%29%5E2-%5B4%5Ctimes8%5Ctimes%28-95%29%5D%7D%20%7D%7B2%5Ctimes8%7D)
Therefore t= 5.98 or -1.98
since time can not be negative So , t=5.98 s
Therefore the ball strikes the ground 5.98 s after kick.
For 36 3 6 13. For 48 4 8 24. I think there are more but I can't think of them
Answer:
a. ∆EGF ≅ ∆EGD
Step-by-step explanation:
Congruent triangles would have the same side lengths and the same measure of angles.
From the figure given:
EG in ∆EGF ≅ EG in ∆EGD
GF in ∆EGF ≅ GD in ∆EGD, also
EF ≅ ED.
The three angles in ∆EFG are also congruent to the three angles in ∆EGD.
Therefore, ∆EGD is congruent to ∆EGF.
∆EGF ≅ ∆EGD
Answer:
0.5
Step-by-step explanation:
I found this out because I am smart
Because none of the points on the number line are above 0, we know that the points will be negative.
This eliminates the second and third choices, as they contain positive numbers.
The first point, A, is a number less than -0.5 or -1/2
The first choice matches A with -5/16, which is less than -0.5 or -1/2
Therefore, the fourth choice must be the correct answer.
