Answer:
The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Step-by-step explanation:
The equation of the parabola is:
Compute the first order derivative of <em>y</em> as follows:
![\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bd%7Dy%7D%7B%5Ctext%7Bdx%7D%7D%3D%5Cfrac%7B%5Ctext%7Bd%7D%7D%7B%5Ctext%7Bdx%7D%7D%5B0.00035x%5E%7B2%7D%5D)
Now, it is provided that |<em>x </em>| ≤ 605.
⇒ -605 ≤ <em>x</em> ≤ 605
Compute the arc length as follows:
Now, let
Plug in the solved integrals in Arc Length and solve as follows:
Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
the equation of a line in point-slope form is
y - b = m(x - a)
where m is the slope and (a, b ) is a point on the line
y + 1 = 
(x + 5) is in this form
(a) with slope =
(b) point on the line = (- 5, - 1 ) = (a, b)
Slope intercept form is y=mx+b because m=slope and b=y-intercept hence "slope intercept form"...
m=deltay/deltax=(0-5)/(-9--6)=-5/-3=5/3 so far we have now:
y=5x/3 +b, using any point, I'll use (-9,0) we can now solve for b or the y-intercept...
0=-9(5)/3 +b
0=-15+b, so b=15 and our line is:
y=5x/3 + 15 or more neatly
y=(5x+45)/3
Answer: The plane was flying at 40.3636 mph
Step-by-step explanation: Simply divide the total miles by how fast the plane was going.
$18,617.75 is the answer
$87,525-$77,100=$10,425 (the amount over $77,100)
$10,425 x .28=$2,919 (the 28% taxed amount over $77,100)
$2,919+$15,698.75 (the already taxed amount in the chart)=$18,617.75
