Answer:
44%
Step-by-step explanation:
1) You divide 209 by 475
2) Take 0.44 and move the decimal over 1 place to make <u>44%</u>
4(a+12)=32
4a+48=32
4a=-16
a=-4
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions ()
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME= where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME= ≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
x = 38
y = 25
Step-by-step explanation:
To find x, you do
(2x + 5) = (3x - 33)
Subtract 2x from both sides to isolate x on one side, you get:
5 = (x - 33)
Add 33 to both sides to separate the normal number from the x, you get:
38 = x
From there, you plug x into one of the equations
2(38) + 5
The answer's 81, meaning that angle is 81 degrees. Using supplementary angles, you can find that angle ACD = 99, which you can use to find angle BCE. You'll get this equation:
(4y - 1) = 99
Add one to both sides to get rid of it, you get:
4y = 100
Divide by four, to get the y all alone:
y = 25
I hope this helped!
Answer:
∡TQS = 10x -3
Step-by-step explanation:
∡TQS = ∡RQS - ∡RQT
= 22x - 11 - (12x - 8)
= 10x -3