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3 years ago

Consider the following reaction.

Chemistry

2 answers:

shusha [124]3 years ago

8 0

The answer is D if ringt can i have a thanx

slava [35]3 years ago

3 0

Try looking at the oxidation numbers of each component and how they change in the reaction.
Oxidation of Oxygen will always stay -2 (unless it is bonded to fluorine)
The overall oxidation number of the compund/ molecule must add up to 0.

Oxy no. in reactants Oxy no. in products red/oxy
Components:
Carbon +4 +2 Reduced
Oxygen -2 -2 Unchanged
Hydrogen 0 +1 Oxidised

Therefore, since the oxidation number of the Hydroden increased, Hydrogen has been oxidised.

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20 pts. I am making holiday cookies and the recipe says that it will make 48 cookies. After eating some raw cookie dough I bake

Nikitich [7]

Check the attached file for the answer.

5 0

3 years ago

CH3OH can be synthesized by the following reaction.

puteri [66]

Answer:

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

Explanation:

Step 1: Data given

CO(g)+2H2(g)?CH3OH(g)

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.04 g/mol

Step 2: What volume of H2 gas (in L), measured at 754mmHg and 90?C, is required to synthesize 23.0g CH3OH?

Pressure = 754 mmHg = 0.992 atm

Temperature = 90°C = 363 Kelvin

mass of CH3OH produced = 23.0 grams

Step 3: Calculate moles of CH3OH

Moles CH3OH = mass CH3OH / Molar mass CH3OH

Moles CH3OH = 23.0 grams / 32.04 g/mol

Moles CH3OH = 0.718 moles

Step 4: Calculate moles of H2

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

For 0.718 moles CH3OH produced, we have 2*0.718 moles =1.436 moles of H2 and 0.718 moles of CO

Step 5: Calculate volume of H2

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 1.436 moles H2

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (1.436*0.08206*363)/0.992

V = 43.12 L

Step 6: Calculate volume of CO

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 0.718 moles CO

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (0.718*0.08206*363)/0.992

V = 21.56 L

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

3 0

3 years ago

If the Earth rotated in the opposite direction, what would most likely occur? Select one

Ulleksa [173]

Answer:

,jgkgchgchgcchgchg

Explanation:

5 0

3 years ago

Where are the most massive elements found on the periodic table?

iragen [17]

By atomic radius, the bottom left

5 0

3 years ago

Read 2 more answers

Draw the structure of ozone according to VSEPR theory. What would be its associated molecular geometry?

vodka [1.7K]

Answer: Ozone's molecular geometry can be described as bent.

Explanation:

The molecular geometry of the O3 groups has a trigonal planar arrangement.

Here is a quick explanation of the molecular geometry of O3 including a quick description of the O3 bond angles.

Examining the Lewis structure of O3 we can see that there are a pair of unbounded valence electrons at the top of the structure.

Based on VSEPR Theory (Valence Shell Electron Pair Repulsion Theory) these electrons will repel the electron clouds of the two oxygen atoms on the end.

As a result they will be pushed down giving the 03 molecule a bent molecular geometry or shape.

The 03 bond angle will be 116° degrees since it has a Bent molecular geometry

8 0

3 years ago