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GenaCL600 [577]
3 years ago
8

Consider the following reaction.

Chemistry
2 answers:
shusha [124]3 years ago
8 0
The answer is D if ringt can i have a thanx
slava [35]3 years ago
3 0
Try looking at the oxidation numbers of each component and how they change in the reaction. 
Oxidation of Oxygen will always stay -2 (unless it is bonded to fluorine) 
The overall oxidation number of the compund/ molecule must add up to 0.

                              Oxy no. in reactants             Oxy no. in products     red/oxy   
Components: 
Carbon                               +4                                              +2               Reduced
Oxygen                               -2                                              -2              Unchanged
Hydrogen                            0                                               +1               Oxidised
 
Therefore, since the oxidation number  of the Hydroden increased, Hydrogen has been oxidised.
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Explanation:

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3 years ago
What is the product of the unbalanced equation below?
inessss [21]

Answer:

C. HCI(g)

Explanation:

The following equation between hydrogen gas (H2) and oxygen gas (O2) is given below:

H2(g) + Cl2(g) ►

Based on these unbalanced equation, the products of the reaction was not given, however, if one molecule of hydrogen and oxygen combine, hydrogen chloride (HCl) should be produced as the product of the reaction as in:

H2(g) + Cl2(9) ► 2HCl(g)

4 0
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What are three common examples of nuclear energy?
Elena L [17]
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3) </span><span>Nuclear power plant - controlled fission reaction suplies homes with electric energy.
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5 0
3 years ago
When a negatively charged species is most appropriately depicted as a hybrid of several resonance forms, the negative charge pre
Varvara68 [4.7K]

Answer:

True

Explanation:

Resonance is a concept that was introduced when it was not possible to represent a compound with a single Lewis structure. Lewis formulas represent localized electrons, either shared by two atoms in a covalent bond or as non-shared electrons belonging to a given atom. Certain organic compounds, especially those containing multiple bonds can be described by more than one Lewis structure. In these cases, the true Lewis structure has an electronic distribution that is a "hybrid" of all possible Lewis structures of that molecule. Each of Lewis's structures is known as resonance or canonical forms and they are related to each other by a double-headed arrow, where all possible positions of electrons in that molecule are represented.

This type of compound has multiple bonds (double or triple) where electrons are not fixed, but move quickly between atoms, "resonating" between the different Lewis structures. For this reason, when a resonance hybrid has a negative charge, this charge moves between the different resonant structures.

Many times, an intermediate Lewis structure is drawn, with dotted lines, simulating approaching the real structure of the compound, and where this phenomenon of electron and charge mobility can be observed. For example, as we can observe in the ozone resonance image.

5 0
3 years ago
A sample of gas contains 0.1900 mol of CO(g) and 0.1900 mol of NO(g) and occupies a volume of 22.0 L. The following reaction tak
worty [1.4K]

Answer:

V₂ = 16.5 L

Explanation:

To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:

V₁/n₁ = V₂/n₂

In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

  • n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol

<em>We use the reaction to calculate n₂</em>:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

  • mol CO₂:

0.1900 mol CO * \frac{2molCO_{2}}{2molCO} = 0.1900 mol CO₂

  • mol N₂:

0.1900 mol NO * \frac{1molN_{2}}{2molNO} = 0.095 mol N₂

  • n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol

Calculating V₂:

22.0 L / 0.3800 mol = V₂ / 0.2850 mol

V₂ = 16.5 L

3 0
4 years ago
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