Question

3. Silver nitrate. AgNO. reden woh sodium chloride as:

Answer 1

Answer:

0.04mol of NaCl and 0.04mol of AgNO3

Explanation:

To calculate the numbers of mole of NaCl and AgNO3 used in the reaction, first we obtained their mole before the reaction as illustrated below:

For NaCl:

Molarity = 0.2M

Volume = 200mL = 200/1000 = 0.2L

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.2 x 0.2 = 0.04mol

For AgNO3:

Molarity = 0.5M

Volume = 100mL = 100/1000 = 0.1L

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.5 x 0.1 = 0.05mol

NaCl + AgNO3 —> AgCl + NaNO3

From the above equation,

1mole of NaCl required 1mole of AgNO3.

Therefore for, 0.04mol of NaCl will also require 0.04mol of AgNO3. This implies that AgNO3 is the excess reactant