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nasty-shy [4]
3 years ago
5

2/10 as a mixed number

Mathematics
2 answers:
kogti [31]3 years ago
7 0

0.2 if you mean 2/10 or 2.5 if you mean 10/2


serg [7]3 years ago
7 0

The fraction 2/10 can't be converted into a mixed number since it's not an improper fraction.

If you mean 10/2, that can be converted into a mixed fraction, and that would 5 since the number 2 can be multiplied by 5 to get 10.

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Help pls ill award u the brainliest person!!! plsss help nowwww
Genrish500 [490]

Answer:

Photo 1: (a) C

(b) A

(c) D

Photo 2: 12.0416cm

Photo 3: 15.5242cm

Step-by-step explanation:

Photo 1: (a) 6×4=24

(b) 6(5)+6=36

(c) 6×6=36

Photo 2: Using Pythagoras' Theorem,

Unknown side length= square root symbol [(8×8)+(9×9)]

= 12.0416cm (6sf)

Photo 3: Using Pythagoras' Theorem,

AC= square root symbol (AB^2+BC^2)

=square root symbol [(15×15)+(4×4)]

= 15.5242cm (6sf)

4 0
2 years ago
Help I’m sooo lost!!
Luba_88 [7]
In these questions, they're asking you to express x in terms of the other algebra.
So we can simply solve this by imaging them as real numerical values.

rx - sx + y = b
First shift +y to the other side, change it to negative.
rx - sx =b - y
Factories rx - sx by picking out the common factor x.
x ( r - s) = b - y
Shift (r-s) to the other side, and we're done.
x = b - y / r - s
Therefore, the final answer is
x =  \frac{b - y}{r - s}

4 0
3 years ago
Read 2 more answers
4{2a(3a-b)+3ab}+5{3b(a+2b)-4ab}
Paraphin [41]
Follow order of operations.
Distribute what is in the parentheses.
4[6a^2 -2ab +3ab] + 5[3ab + 6b^2 -4ab]

Combine like terms in the brackets.
4[6a^2 + 3ab] + 5[-1ab + 6b^2]

Distribute the 4 and the 5.
24a^2 + 12ab -5ab + 30b^2

Combine like terms.
24a^2 +7ab + 30b^2

That's your final answer:
24a^2 +7ab + 30b^2
5 0
3 years ago
Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2
zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

Step-by-step explanation:

Un par ordenado es un elemento de la forma (x,f(x)), donde x es un elemento del dominio de la función, mientras f(x) es la imagen de la función evaluada en x. Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

x \rightarrow f(x)

Dado que f(x) es una función polinómica, existe una imagen para todo elemento x. Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

f(0) = 0^{3}-2\cdot (0)^{2}-2

f(0) = -2

(0, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 1

f(1) = 1^{3}-2\cdot (1)^{2}-2

f(1) = -3

(1, -3) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 2

f(2) = 2^{3}-2\cdot (2)^{2}-2

f(2) = -2

(2, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 3

f(3) = 3^{3}-2\cdot (3)^{2}-2

f(3) = 7

(3, 7) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

6 0
3 years ago
In a class of 21 students, there are 3 boys for every 4 girls. How many girls in all are in the
Eduardwww [97]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
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