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Stella [2.4K]
3 years ago
13

Find the directrix of the parabola y = (1/8)(x – 5)2 - 3.

Mathematics
1 answer:
V125BC [204]3 years ago
6 0
I have no idea. Quick question for you though since we are working on similar stuff. How do I write this equation in graphing form: y=2x^2-12x+19
You might be interested in
Subtract fraction and simplify if needed
Harrizon [31]
First you need to find the common denominator. both 6 and 7 go in to 42 evenly

multiply 5/6 by 7 to get 35/42
multiply 2/7 by 6 to get 12/42
subtract 12 from 35 to get 23

23/42
6 0
3 years ago
rachel is frosting the top of two cakes and wants to know which cake will require more frosting. one cake is round with a diamet
Jet001 [13]

Answer:

The square cake is has a larger area by about 40.73 square inches

Step-by-step explanation:

Find the area of the top of each cake.

The square cake has an area of 81 sq inches,   ( length x width = Area, the

                                                                                    length is 9)

The round cake has an area of 16π, which is about 50.27 square inches

  (A = πr², here r is 4, radius is half the diameter)

81 - 16π =  81 - 50.27 =  40.73 square inches

4 0
3 years ago
Solve the system of equations using the substitution method. 2x+8y=4 x=−3y+5
goldenfox [79]
Since x=-3y+5, substitute x for -3y+5. 

2(-3y+5)+8y=4

Distribute. 

-6y+10+8y= 4

2y+10= 4

Subtract 10 on both sides. 

2y=-6

Divide by 2.

y=-3

Plug in y=-3. 

x=-3(-3)+5
x= 9+5
x=14

(14,-3)

We can check this. 

2(14)+8(-3)=4
28-24=4
4=4 <== this works

I hope this helps!
~kaikers
7 0
4 years ago
Use the formula C= dxd
zysi [14]

Answer:

69.08m

Step-by-step explanation:

Circumference of a circle = πd where

d is the diameter of the circle

Given

diameter = 22metres

circumference of the circle = 3.14(22)

circumference of the circle  = 69.08m

Hence the circumference of the circle is 69.08m

5 0
3 years ago
Read 2 more answers
On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)
xz_007 [3.2K]

Answer:

P = 10 + 2\sqrt{53} units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3),  X (2, 3),

Y (4, -4),  Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

For WX:

(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)

WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}

WX = \sqrt{(-5)^2 + (0)^2}

WX = \sqrt{25}

WX = 5

For XY:

(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)

XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}

XY = \sqrt{-2^2 + (3 +4)^2}

XY = \sqrt{-2^2 + 7^2}

XY = \sqrt{4 + 49}

XY = \sqrt{53}

For YZ:

(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)

YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}

YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}

YZ = \sqrt{7^2 + (-2)^2}

YZ = \sqrt{49 + 4}

YZ = \sqrt{53}

For ZW:

(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)

ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}

ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}

ZW = \sqrt{0^2 + (-5)^2}

ZW = \sqrt{0 + 25}

ZW = \sqrt{25}

ZW = 5

The Perimeter (P) is as follows:

P = WX + XY + YZ + ZW

P = 5 + \sqrt{53} + \sqrt{53} + 5

P = 5 + 5 + \sqrt{53} + \sqrt{53}

P = 10 + 2\sqrt{53} units

6 0
4 years ago
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