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-Dominant- [34]
3 years ago
11

In solving a rate of increase problem,the original value is always the?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0
<span>In solving a rate of increase problem,the original value is always the percent of new value. Hope this answers the question. Have a nice day. Feel free to ask more questions. Thank you.</span>
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consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side len
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The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Given that,

y forms a circle of radius r

y=2\pir

r=y/2\pi

(2-y)- forms Square Side x

(2-y) = 4x

x=(2-y)/4

Now Sum of Area's=Area of Square +Area of Circle

Sum = \pir² + x²

Substitute the r and x values in above equation,

A(y)= y²/4\pi+(y-2)²/ 16

To maximize Area A(y)

A'(y)= 0

2y/4\pi + 2(y-2)/16 =0

y/2\pi + (y-2)/8 =0

y = 2\pi/\pi+4

Y max will be max, x to be maximum.

for maximum sum of areas,

x=2/\pi+4

Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

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Step-by-step explanation:

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