Answer:
2) Equation 1 and Equation 2 have the same number of solutions.
Step-by-step explanation:
The two given equations are
1) 15x + 6 = 41 and 2) 2x + 13 = 28
Solving both equations, we get
Solving (1) : 15x + 6 = 41 ⇒ 15x = 41 - 6 = 35
or, x = 35/15 ⇒ x = 7/3
Solving (2) : 2x + 13 = 28⇒ 2x = 28 - 13 = 15
or, x = 15/2 ⇒ x = 15/2
So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.
Find the equation of the inverse.
we have
step 1
Exchange the variables
x for y and y for x
step 2
Isolate the variable y
apply log both sides
step 3
Let
therefore
the inverse function is
Well 6^2 is 36 so my best estimate is 6
The product of 8 and 54 is 46
Let's say the cost of student tickets is x and the cost of adult tickets is y. Then:
(1) 12y + 6x = 138
(2) 5y + 11x = 100
If we rearrange equation (1) we get:
12y = 138 - 6x
Now divide each side by 12:
y = 11.5 - 0.5x
We can now substitute this into equation (2):
5(11.5 - 0.5x) + 11x = 100
57.5 - 2.5x + 11x = 100
8.5x = 42.5
x = 5, therefor the cost of a student ticket is $5.00
