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Shkiper50 [21]
3 years ago
14

Classify each figure on the triangle

Mathematics
2 answers:
lara31 [8.8K]3 years ago
6 0
My answer video hope it helps you welp welp

ipn [44]3 years ago
5 0
All the triangles are isosceles meaning that they have to sides that are equal 
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The position of a diving bell is −3/4 mile relative to sea level. The diving bell reached this position after dropping from sea
Natalija [7]
<span>After 1 hour, the diving bell was -1/2 mile relative to sea level. Since the rate of decent is constant, we can use two ratios to represent the depth at 2 different times. To make things easier to write, I'll use decimals to represent time and depth. -.75 / 1.5 = x / 1 Now solve for x -0.5 = x So after 1 hour, the diving bell was -1/2 mile relative to sea level.</span>
6 0
3 years ago
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BartSMP [9]
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6 0
3 years ago
Read 2 more answers
Factor completely. 2x^4+4x^3-30x^2
kramer

Answer:

Step-by-step explanation:

2x⁴ + 4x³ - 30x² = 2x²*(x² + 2x - 15)

x² + 2x - 15

Sum = 2

Product = -15

Factors = 5 ; (-3)

x² + 2x - 15 = x² + 5x - 3x - 3 *5

                  = x(x + 5) - 3(x + 5)

                  = (x + 5)(x - 3)

2x⁴ + 4x³ - 30x² = (2x²) (x + 5)(x - 3)

7 0
3 years ago
Before a bag of flour can be sold, it must be 40 kilograms but can be within 0.5
Serjik [45]

Answer:

The minimum acceptable weight of the flour bag is 39.5 kg,

and its maximum acceptable weight is 40.5 kg

Step-by-step explanation:

Notice that the selling weight of the bag to be sold (x) needs to differ from 40 kg at most 0.5 kg. Therefore, we can write the following inequality:

|x-40|\leq 0.5

The inequality can be solve once we remove the absolute value symbol, and solve for the unknown "x". Recall that in order to solve it, we need to consider the two possible cases:

a) that the expression within the absolute value symbol is larger than or equal to zero, and b) that the expression is less than zero.

a) If x-40\geq 0 then its absolute value is equal to itself (x-40), and when we remove the absolute value symbols, we get:

x-40\leq 0.5\\x\leq 0.5+40\\x\leq 40.5\,\,kg

which means that the weigh "x" of the flour bag should be smaller or equal than 40.5  kg

b) If x-40, then the absolute value of this is its opposite : -x+40, and the inequality becomes:

-x+40\leq 0.5\\40\leq 0.5+x\\40-0.5\leq x\\39.5\leq x

which means that the weight of the flour bag must be larger than or equal to 39.5 kg

So, the minimum acceptable weight of the flour bag is 39.5 kg, and the maximum acceptable weight is 40.5 kg

6 0
3 years ago
Hello, could someone please help me find three pairs for this question
amid [387]

Answer:

x - y = -3        x + y = 9

x      y            x     y

-2 , 1              -2 , 11

-1 , 2              -1 , 10

0 , 3               0 , 9

1 , 4                1 , 8

2 , 5                2 , 7

Hope this helps.

7 0
2 years ago
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