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MatroZZZ [7]
3 years ago
14

What is the ratio 15 : 24 written in lowest terms?

Mathematics
2 answers:
enot [183]3 years ago
7 0
15:24
divide both sides by 3
b. 5:8
for 6:30
divide both sides by 6
1:5
Nadya [2.5K]3 years ago
4 0

its b i done the test

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1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
Write an equation for the vertical translation.<br> y=3/7x<br> 18 units up
Masja [62]
<span>y=3/7x + 18

Hope this helps
</span>
8 0
3 years ago
Solve the proportion.<br> 3/5 = x/10<br> x= [?]
uranmaximum [27]
6 is the only possible answer
7 0
2 years ago
Read 2 more answers
If ax2 + bx + c = 0 then
Alexeev081 [22]
3x² + 10x + 6 = 0
x = -(10) ± √((10)² - 4(3)(6))
                       2(3)
x = -10 ± √(100 - 72)
                   6
x = -10 ± √(28)
              6
x = -10 ± 2√(7)
              6
x = -5 ± √(7)
           3
x = -1²/₃ ± ¹/₃√(7)






5x² - 6x + 1 = 0
x = -(-6) ± √((-6)² - 4(5)(1))
                     2(5)
x = 6 ± √(36 - 20)
               10
x = 6 ± √(16)
          10
x = 6 ± 4
        10
x = 3 ± 2
         5
x = 3 + 2    or    x = 3 - 2
         5                       5
x = 5    or    x = -1
      5                  5
x = 1    or    x = -0.2






2x² - 7x - 15 = 0
x = -(-7) ± √((-7)² - 4(2)(-15))
                       2(2)
x = 7 ± √(49 + 120)
                 4
x = 7 ± √(169)
             4
x = 7 ± 13
          4
x = 7 + 13    or    x = 7 - 13
          4                         4
x = 20    or    x = 6
       4                  4
x = 5    or    x = 1.5






x² + 4x + 1 = 0
x = -(4) ± √((4)² - 4(1)(1))
                   2(1)
x = -4 ± √(16 - 4)
                2
x = -4 ± √(12)
             2
x = -4 ± 2√(3)
             2
x = -2 ± √(3)
           2
x = -1 ± ¹/₂√(3)
x = -1 + ¹/₂√(3)    or    x = -1 - ¹/₂√(3)
4 0
3 years ago
What is the product?
Angelina_Jolie [31]

The answer is the first one. You know because -4x x 5 is -20x and this option is the only one with -20x included.

7 0
3 years ago
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