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4 years ago

Who can do this question, I don't know how to do...this is difficult for me....who can teach me?

Mathematics

1 answer:

cupoosta [38]4 years ago

4 0

We know that AB and CD are parallel. This allows many assumptions.
From that we know that angle A and angle D are congruent.
That means that x + 8 = 2x - 22 and we can solve for x
x + 8 = 2x - 22
x + 30 = 2x
30 = x or x = 30

We know from the figure that angle B is x or now that we solved for x is 30 degrees. Also, we know that both angle A and angle D are 38 degrees. Now we can solve for the vertical angle E which has a measure of y degrees. A triangle has the sum of its angles equal to 180 degrees.

We can set up an equation like this 30 + 38 + y = 180
30 + 38 + y = 180
68 + y = 180
y = 112 degrees

That is how you would solve this problem

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1.4 repeating?

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3 years ago

Graph the line with a slope of 2/5 that goes through (3,1)

Triss [41]

Answer:

$y = \dfrac{2x}{5} - \dfrac{1}{5}$

Step-by-step explanation:

Given:

$\bullet \ \ \text{Slope of line:}\ \dfrac{2}{5} \\\\ \bullet \ \text{Passes through:} \ (3, 1)$

To determine the equation of the line, we will use point slope form.

Formula of point slope form:

→ y - y₁ = m(x - x₁)

Where "x₁" and "y₁" are the coordinates of the point and "m" is the slope.

Substitute the coordinates and the slope:

$:\implies y - 1 = \dfrac{2}{5} (x - 3)$

Simplify the R.H.S:

$:\implies y - 1 = \dfrac{2x}{5} - \dfrac{6}{5}$

Add 1 both sides:

$:\implies y - 1 + 1 = \dfrac{2x}{5} - \dfrac{6}{5} + 1$

Simplify the equation:

$:\implies y = \dfrac{2x}{5} - \dfrac{6}{5} + \dfrac{5}{5}$

$:\implies \boxed{y = \dfrac{2x}{5} - \dfrac{1}{5}}$

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In this case, we are already given a point (3, 1). We can simply plot the y-intercept $[\bold{\frac{-1}{5} }]$ on the coordinate plane. Then, we can draw a straight line through both points. It is suggested that you use a ruler to do so.

Graph attached**

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hjlf

Answer: (4)

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Step-by-step explanation:

To represent the absolute value of a number (or a variable), we write a vertical bar on either side of the number. For example, the absolute value of 4 is written as |4|.

Also, the absolute value of -4 is written as |-4|. As we discussed earlier, the absolute value results in a non-negative value all the time.

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