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Wewaii [24]
4 years ago
8

Who can do this question, I don't know how to do...this is difficult for me....who can teach me?

Mathematics
1 answer:
cupoosta [38]4 years ago
4 0
We know that AB and CD are parallel.  This allows many assumptions.
From that we know that angle A and angle D are congruent. 
That means that x + 8 = 2x - 22 and we can solve for x
x + 8 = 2x - 22
x + 30 = 2x
30 = x or x = 30

We know from the figure that angle B is x or now that we solved for x is 30 degrees.  Also, we know that both angle A and angle D are 38 degrees.  Now we can solve for the vertical angle E which has a measure of y degrees.  A triangle has the sum of its angles equal to 180 degrees.

We can set up an equation like this 30 + 38 + y = 180
30 + 38 + y = 180
68 + y = 180
y = 112 degrees

That is how you would solve this problem
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42

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42 is the answer

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A tub filled with 50 quarts of water empties at a rate of 2.5 quarts per minute. let w = quarts of water left in the tub and t =
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This is a linear relationship. The slope-intercept form of the linear equation is:

y=mx+c

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<u><em>Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)</em></u>

<u><em>Initial value is 50 quarts, so c is 50.</em></u>

Plugging in the values we get y=-2.5x+50.


Changing variables to w instead of y and t instead of x, gives us,

w=50-2.5t. Where w is warts of water left in the tub and t is the time in minutes.


There is no viable solution when t=30 because at t=20, w=0 (0=50-2.5(20)). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.


ANSWER:

Modelling equation: w=50-2.5t

When t=30, there is no VIABLE solution

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Step-by-step explanation:

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A group of volunteers has been collecting toys to deliver to a local charity. Over the last 5 days, the volunteers have collecte
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Answer:

  • Their rate was 85 toys per day.

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<u>Given equation:</u>

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13 1/3 and  6 2/3.

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Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

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x( 40 - 3x) = 0

40 - 3x = 0

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x = 40/3.

This is a maximum because the second derivative y" =  40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and  6 2/3.

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