Answer:
42
Step-by-step explanation:
42 is the answer
This is a linear relationship. The slope-intercept form of the linear equation is:

Where,
- m is the rate of change (positive if increasing rate and negative if decreasing rate)
- c is the y intercept, or the initial value
<u><em>Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)</em></u>
<u><em>Initial value is 50 quarts, so c is 50.</em></u>
Plugging in the values we get
.
Changing variables to w instead of y and t instead of x, gives us,
. Where w is warts of water left in the tub and t is the time in minutes.
There is no viable solution when t=30 because at t=20, w=0 (
). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.
ANSWER:
Modelling equation: 
When
, there is no VIABLE solution
Answer:
Step-by-step explanation:
132
Hope I helepd
Answer:
- Their rate was 85 toys per day.
Step-by-step explanation:
<u>Given equation:</u>
<u>Now, let's solve the equation:</u>
Their rate was 85 toys per day.
Answer:
13 1/3 and 6 2/3.
Step-by-step explanation:
Let the 2 parts be x and (20 - x).
So x^2(20 - x) must be a maximum.
y = x^2(20 - x)
y = 20x^2 - x^3
Finding the derivative):
y' = 40x - 3x^2 = 0 for maxm/minm value.
x( 40 - 3x) = 0
40 - 3x = 0
3x = 40
x = 40/3.
This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.
So the 2 numbers are 13 1/3 and 6 2/3.