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Musya8 [376]
2 years ago
13

3(x + 1) = 5(x - 2) + 7 x=?

Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0
Those are called binomials & you have to use the distributive property.
first: 3(x+1) distributed & simplified 3x+3 & 5(x-2) distributed & simplified is 5x-10, therefore 3(x+1) = 3x+3 & 5(x-2) = 5x-10. always simplify before solving any algebraic problem! 
second: so now we can say... 3x + 3 = 5x - 10 + 7 .
third: now we combine like terms by adding the -10 & 7 (on the right side) together to get -3.
fourth: now we have to isolate the variables by doing the opposite function on each side! it should look like this right now: 3x + 3 = 5x - 3 ... subtract the 3x, on both sides, from the 5x to get 2x. looks like this now: 3 = 2x - 3
now add the -3 (on the right) on the both sides
looks like this now: 6 = 2x
fifth: now divide to get 3.     X = 3 !!!!!

alukav5142 [94]2 years ago
4 0
1.4 repeating? 


3x+3=5x-10+7x
3x+3=12x-10
3=9x-10
13=9x
1.4 repeating=x
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In a game of rolling a die. If the number showing is even, you win $3, if the number showing is 1 you win $3 and if the number s
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Answer:

(a)

\left|\begin{array}{c|c|c}---&---&---\\x&\$0&\$3\\---&---&---\\P(x)&\dfrac13&\dfrac23\\---&---&---\\\end{array}\right|

(b)$2

Step-by-step explanation:

In the given game of rolling a die. these are the possible winnings.

  • If the number showing is even(2, 4, or 6) or 1, you win $3.
  • If the number showing is either 3 or 5 you win $0.

There are 6 sides in the die.

P($obtaining a 1,2,4 or 6)=\dfrac46=\dfrac23\\P($obtaining a 3 or 5)=\dfrac26=\dfrac13

(i)The probability distribution of x.

Let x be the amount won

Therefore:

Probability distribution of x.

\left|\begin{array}{c|c|c}---&---&---\\x&\$0&\$3\\---&---&---\\P(x)&\dfrac13&\dfrac23\\---&---&---\\\end{array}\right|

(ii) Expected amount of dollar won

Expected Amount

=\sum x_iP(x_i)\\=(0*\dfrac13)+(3*\dfrac23)\\=\$2\\

You would expect to win $2.

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