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Ghella [55]
3 years ago
12

Detailed ___ highest risk warnings can incude identifiying which vendor updates apply to which vulnerablities as well as which t

ypes of defenses have been found to work against the specific vulnerabilities reported.
Computers and Technology
1 answer:
BigorU [14]3 years ago
4 0

Answer:

Intelligence  is the correct answer.

Explanation:

Because the high-risk intelligence is the complicated warning that can be involved in recognizing those vendors who update the following and apply it to the exposure in which defenses have been founded to work against the particular report of the vulnerability. So, that's why the following answer is not false.

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A closed-source product is typically free.TrueFalse
CaHeK987 [17]

Answer:

False

Explanation:

A closed-source product is often closed-source to protect intelectual property and prevent replication.

6 0
4 years ago
Does an android tablet have a hard drive
Kisachek [45]
No, it uses flash menory
3 0
4 years ago
(Count positive and negative numbers and compute the average of numbers) Write a program that reads an unspecified number of int
Papessa [141]

Answer:

Explanation:

Sorry it  is in Java, though you can covert it using converter

public class Exercise {

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int positives = 0;  // Count the number of positive numbers

 int negatives = 0;  // Count the number of negative numbers

 int count = 0;   // Count all numbers

 double total = 0;  // Accumulate a totol

 // Promopt the user to enter an integer or 0 to exit

 System.out.print("Enter an integer, the input ends if it is 0: ");

 int number = input.nextInt();

 if (number == 0) { // Test for sentinel value

  System.out.println("No numbers are entered except 0");

  System.exit(1);

 }

 while (number != 0) {// Test for sentinel value

  if (number > 0)

   positives++; // Increase positives

  else

   negatives++; // Increase negatives

  total += number; // Accumulate total

  count++;    // Increase the count

  number = input.nextInt();

 }

 // Calculate the average

 double average = total / count;

 // Display results

 System.out.println(

  "The number of positive is " + positives +

  "\nThe number of negatives is " + negatives +

  "\nThe total is total " + total +

  "\nThe average is " + average);

}

}

7 0
3 years ago
Write a program that computes the sum of the first tenpositive integers, 1 + 2 + ..+ 10.
Stella [2.4K]

Answer:

#include <iostream>  

using namespace std;

int main()

{

  int sum=0;//taking an integer variable to store the sum with initial value 0..

  for(int i=1;i<=10;i++)//looping from 1 to 10..

  {

      sum+=i;//adding each i in the sum..

  }

  cout<<sum<<endl;//printing the sum..

   return 0;

}

Explanation:

output :- 55

1.I have taken an integer variable sum which is equal to 0.

2.Looping over first ten positive integers.

3.Adding every number to sum.

4.Printing the sum.

6 0
3 years ago
For a list of numbers entered by the user and terminated by 0. Write a program to find the sum of the positive numbers and the s
Mumz [18]

Answer:

Following are the program in the Python Programming Language

#set variables to 0

positive_sum=0

negative_sum=0

#print message

print("Enter 0 to terminate")

#set the while loop

while(True):

 #get input from the user

 num=float(input("Enter positive or negative numbers: "))

 #set if statement to check condition

 if(num==0):

   break

 elif(num>0):

   positive_sum+=num

 else:

   negative_sum+=num

#print output with message

print()

print("sum of positive numbers: ", positive_sum)

print("sum of negative numbers: ", negative_sum)

<u>Output:</u>

Enter 0 to terminate

Enter positive or negative numbers: 1

Enter positive or negative numbers: 3

Enter positive or negative numbers: 5

Enter positive or negative numbers: -7

Enter positive or negative numbers: -2Enter positive or negative numbers: 0

sum of positive numbers:  9.0

sum of negative numbers:  -9.0

Explanation:

Here, we set two integer data type variables "positive_sum", "negative_sum" and initialize to 0.

Then, we set the while infinite loop inside the loop.

  • Set a variable "num" and get input from the user in it.
  • Set the if conditional statement and check condition the variable "num" is equal to 0 then, loop will terminate.
  • Set the elif statement and check condition the variable "num" is greater than 0 then, add that input and store in the variable "positive_sum"
  • Otherwise, add that input and store in the variable "negative_sum".

Finally, we print the output with the message.

6 0
4 years ago
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