Answer: 188 is the outlier
Step-by-step explanation:
Find median of the whole data set. The median is 83.5.
Then find Q1 and Q3. Q1 is 78, Q2 is 96.
Then find the IQR. The IQR is 18.
Find the inner fences of the data set. The inner fences are 51 and 123. Anything that is outside of 51 or 123 is an outlier so 188 is an outlier.
P(A/B) = P(A∩B) / P(B)
P(A/B) = (3/10) / (2/5) = 3/10 x 5/2 = 15/20 = 3/4
1. 319
2. 77
3.60
4.c
I hope it helps
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155
OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.
Step-by-step explanation:
19 m = 0.019 km
28 m = 0.028 km
686 m = 0.686 km
75 km 6 m = 75.006 km
8282 m = 8.282 km
hope this answer helps you dear...take care!