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kow [346]
3 years ago
10

Helppppp what is 5x 89

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

Answer:

The answer should be 445. Unless the "x" is a variable, then its 445x.

You might be interested in
Is it ever possible that cos(A−B)=cos ⁡A − cos ⁡B?
son4ous [18]

Answer:

yes

Step-by-step explanation:

I'm going to give you a slightly different answer, but it's going to make sense :-)

First, let's review what "sin" and "cos" really mean. They are functions that take as an input an angle, which we call theta. They output the base (cos) and height (sin) of a triangle which as a hypotenuse of length 1.    

Now, let's pick some examples. If we happen to set theta to 45 degress, you will get a triangle that looks like this:

In this case, both sin(theta) and cos(theta) are the same number, the square root of 1/2. So cos(theta) + cos (theta) is 2 times the square tool of 1/2.

Now imagine that we now want to find cos (theta + theta). Remember that theta was 45 degrees, so this will be cos (45 + 45), or cos (90).

But remember that cos is the base of a triangle where theta is the angle with the base. Well, that's not a triangle at all, is it? It's just a vertical line. In fact, cos(90) will be zero.

5 0
3 years ago
Please I need help I don't understand
mario62 [17]

Answer:

Step-by-step explanation:

from the graph of f(x)

when x=1,f(x)=0

or f(1)=0

when f(x)=2,x=2

for g(x)

when x=6,g(x)=16

or g(6)=16

when g(x)=18,x=32

for h(x)

when x=14

h(x)=27x-7

h(14)=27×14-7=7(27×2-1)=7(54-1)=7×53=371

h(x)=-493

27x-7=-493

27 x=-493+7=-486

3 x=-54

x=-18

for p(t)

when t=94

p(t)=24

p(94)=24

p(t)=67

t=31

8 0
4 years ago
Number 9 last question
andreyandreev [35.5K]
The answer would be the second one, you can immediately cross off the first one and 3rd one, 2 x 200 = 400 - 300 = 100 :)
8 0
4 years ago
What expression is equivalent to
kaheart [24]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \sqrt[3]{64a^6b^7c^9}

By simplifying this expression,

\sqrt[3]{64a^6b^7c^9}=\sqrt[3]{(4)^3(a^2)^3(b^2)^3(b)(c^3)^3}

                 =(4a^2b^2c^3)\sqrt[3]{b}

Option (1)

2abc^2\sqrt[3]{4a^2b^3c} = 2ab^2c^2\sqrt[3]{a^2c}

Option (2)

4a^2b^2c^3(\sqrt[3]{b}) [Fully simplified form]

Option (3)

8a^3b^3c^4(\sqrt[3]{bc} ) [Fully simplified form]

Option (4)

8a^2b^2c^3(\sqrt[3]{b})

Expression given in Option (2) is equivalent to the given expression.

Option (2) will be the answer.

3 0
4 years ago
The sum of four times a number and 18 is the same as the difference of fourteen and twice a number
Citrus2011 [14]
4x+18=14-2x \\ 4x=-4-2x \\ 6x=-4 \\ x= \frac{2}{3}
4 0
4 years ago
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