Answer:
yes
Step-by-step explanation:
I'm going to give you a slightly different answer, but it's going to make sense :-)
First, let's review what "sin" and "cos" really mean. They are functions that take as an input an angle, which we call theta. They output the base (cos) and height (sin) of a triangle which as a hypotenuse of length 1.
Now, let's pick some examples. If we happen to set theta to 45 degress, you will get a triangle that looks like this:
In this case, both sin(theta) and cos(theta) are the same number, the square root of 1/2. So cos(theta) + cos (theta) is 2 times the square tool of 1/2.
Now imagine that we now want to find cos (theta + theta). Remember that theta was 45 degrees, so this will be cos (45 + 45), or cos (90).
But remember that cos is the base of a triangle where theta is the angle with the base. Well, that's not a triangle at all, is it? It's just a vertical line. In fact, cos(90) will be zero.
Answer:
Step-by-step explanation:
from the graph of f(x)
when x=1,f(x)=0
or f(1)=0
when f(x)=2,x=2
for g(x)
when x=6,g(x)=16
or g(6)=16
when g(x)=18,x=32
for h(x)
when x=14
h(x)=27x-7
h(14)=27×14-7=7(27×2-1)=7(54-1)=7×53=371
h(x)=-493
27x-7=-493
27 x=-493+7=-486
3 x=-54
x=-18
for p(t)
when t=94
p(t)=24
p(94)=24
p(t)=67
t=31
The answer would be the second one, you can immediately cross off the first one and 3rd one, 2 x 200 = 400 - 300 = 100 :)
Answer:
Option (2)
Step-by-step explanation:
Given expression is ![\sqrt[3]{64a^6b^7c^9}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64a%5E6b%5E7c%5E9%7D)
By simplifying this expression,
![\sqrt[3]{64a^6b^7c^9}=\sqrt[3]{(4)^3(a^2)^3(b^2)^3(b)(c^3)^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64a%5E6b%5E7c%5E9%7D%3D%5Csqrt%5B3%5D%7B%284%29%5E3%28a%5E2%29%5E3%28b%5E2%29%5E3%28b%29%28c%5E3%29%5E3%7D)
![=(4a^2b^2c^3)\sqrt[3]{b}](https://tex.z-dn.net/?f=%3D%284a%5E2b%5E2c%5E3%29%5Csqrt%5B3%5D%7Bb%7D)
Option (1)
= ![2ab^2c^2\sqrt[3]{a^2c}](https://tex.z-dn.net/?f=2ab%5E2c%5E2%5Csqrt%5B3%5D%7Ba%5E2c%7D)
Option (2)
[Fully simplified form]
Option (3)
[Fully simplified form]
Option (4)
![8a^2b^2c^3(\sqrt[3]{b})](https://tex.z-dn.net/?f=8a%5E2b%5E2c%5E3%28%5Csqrt%5B3%5D%7Bb%7D%29)
Expression given in Option (2) is equivalent to the given expression.
Option (2) will be the answer.