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3 years ago

Which one don’t lie!!!

Mathematics

2 answers:

Travka [436]3 years ago

7 0

Answer:

Step-by-step explanation:

m=y2-y1/x2-x1

4-2=2

6-3=3

2/3

hope this helps =3

stellarik [79]3 years ago

3 0

Answer:

The answer is 2/3

Step-by-step explanation:

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What is the sum of the prime factors of 2014

goblinko [34]

The sum of prime factors of 2014 is 74

<h3>Solution:</h3>

Given that to find sum of prime factors of 2014

Let us first find the prime factors of 2014

A prime number is a whole number greater than 1 whose only factors are 1 and itself

"Prime Factorization" is finding which prime numbers multiply together to make the original number.

Prime factors of 2014:

The Prime Factorization is:

$2014 = 2 \times 19 \times 53$

Thus the prime factors of 2014 are 2, 19, 53

Let us now find the sum of prime factors of 2014

sum of prime factors of 2014 = 2 + 19 + 53 = 74

Thus the sum of prime factors of 2014 is 74

7 0

3 years ago

) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi

wolverine [178]

Answer:

This code or is program to find a given value of derivative of a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

printf("Enter the coefficient of x to the power %d: ",i);

scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

p = a[deg];

for(i=deg;i>=1;i--)

{

p = (a[i-1] + x*p);

}

return p;

}

8 0

3 years ago

if you horizontally shift the square root parent function, F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormu

Juli2301 [7.4K]

ANSWER

$g(x) = \sqrt{x + 4}$

EXPLANATION

The parent square root function is

$f(x) = \sqrt{x}$

The translation

$g(x ) = \sqrt{x + k}$

Will shift the graph of f(x) k units to left.

The translation

$g(x) = \sqrt{x -k}$

will shift the graph of f(x) to the right by k units.

Therefore if f(x) is shifted 4 units to the left its new equation is:

$g(x) = \sqrt{x + 4}$

7 0

3 years ago

V=3.14(r)^2h solve for r

sveticcg [70]

Assuming the h is not in the exponent, R would equal The square root of V over 3.14h

6 0

3 years ago

Read 2 more answers

Given the function f(x) = x3 + 2x2 − 3x − 5, what is resulting function when f(x) is shifted to the right 1 unit?

cluponka [151]

When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5
= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 
= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 
= x^3 - x^2 - 4x - 1
I hope this helps

5 0

3 years ago

Read 2 more answers