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riadik2000 [5.3K]
3 years ago
7

Find the slope of line AB From the Given figuresplease help me and solve him​

Mathematics
2 answers:
BartSMP [9]3 years ago
4 0

Since, the line AB is parallel to X - axes, so every point on the the line AB will have equal Y - coordinates.

lets take it as Y ( y - coordinate is same )

slope :

=》

\dfrac{y2 - y1}{x2 - x1}

but since y2 and y1 are equal, so

\dfrac{ Y - Y }{x2 - x1}

=》

\dfrac{0}{x2 - x1}

=》

0

makvit [3.9K]3 years ago
3 0

Answer:

slope of AB = 0

Step-by-step explanation:

The slope of the x- axis OX = 0

Since AB is parallel to the x- axis and parallel lines have equal slopes, then

slope of AB = 0

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choose the equation of a line that is perpendicular to the y axis and passes through the point (5,-2)​
kondaur [170]

Answer:

y = -2

Step-by-step explanation:

The line that is perpendicular to y-axis will be a horizontal line so it's slope is 0 => y = 0x + b or y = b

Using (5,-2) => -2 = b => b = -2

then y = -2

3 0
2 years ago
Explain how to find the area of a square if you only know the length of one side is 23 feet? (APAP) 99 POINTS TOO
tatiyna

Answer:

529 feet squared

Step-by-step explanation:

We know that the sides of a square are all the same length, and the formula to find the area of a square is length time width, so to find the area of the square we multiply 23 by 23, or square 23. 23 times 23 equals to 529 so the area of the square is 529 feet squared.

8 0
4 years ago
Simplify 4(2x^3y^4)^4/2(2x^2y^6)^3. Show your work. Please help ASAP!!
vovikov84 [41]

Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

5 0
3 years ago
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