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Fantom [35]
3 years ago
14

Equivalent expression for (x+6)-5+9

Mathematics
1 answer:
Bumek [7]3 years ago
7 0

Answer:

x + 10

Step-by-step explanation:

(x + 6) - 5 + 9 \\  = x + 6 + 4 \\  = x + 10

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Help pls look at question, I'm confused so yeah.
lions [1.4K]

Answer

225 ml

Step-by-step explanation:

90 ml =2 parts

1 part=45

5 parts= 225

5 0
3 years ago
The globe used in social studies class has a diameter of 42 centimeters, What is its volume
Leni [432]

Answer:

Step-by-step explanation: pi r^2

so 42/2 equals 21 radius

volume=22/7 x 21^2

v=1385

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3 years ago
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The net shown can be used to form a cube.
laila [671]

Area of one square = 2 x 2 = 4 square feet

4 square feet x 6 squares = 24 square feet total area

Answer: 24 square feet

5 0
1 year ago
PLS HELP WILL GIVE BRAINIEST! You are flying in an airplane that has 2 engines. The engines individually have a success rate of
Salsk061 [2.6K]

Answer:

.01%*

Step-by-step explanation:

Individually, they both have a rate of failure of 1%.

.01 x .01 = .0001

Therefore they have a combined probability of failure of .01%

*Disclaimer!!

I am not the best at this area in math so I would still reference against someone else's answer, but this is my best effort :)

4 0
3 years ago
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
2 years ago
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