Each van carries 13 students and each bus carries 25 students.
<h3><u>Distribution</u></h3>
Given that the senior class at High School A and the senior class at High School B both planned trips to Yellowstone, and the senior class at High School A rented and filled 5 vans and 2 buses with 115 students, while High School B rented and filled 1 van and 6 buses with 163 students, and each van carried the same number of students and each bus carried the same number of students, to determine the number of students in each van and in each bus, the following calculation must be made:
- 5X + 2Y = 115
- 1X + 6Y = 163
- 5X + 2Y = 115
- 5X + 30Y = 815
- 815 - 115 = 28Y
- 700 = 28Y
- Y = 700 / 28
- y = 25
- 1X + 6x25 = 163
- 1X = 163 - 150
- X = 13
Therefore, each van carries 13 students and each bus carries 25 students.
Learn more about distribution in brainly.com/question/14310262
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The mnemonic SOH CAH TOA helps you remember the relevant trig relationship is
Sin(α) = Opposite/Hypotenuse
sin(α) = (1 ft)/(14 ft)
α = arcsin(1/14) ≈ 4°
The angle the ramp makes with the sidewalk is 4°.
Well you could use the equation 32=2x or 32=(2*x) but if you're looking for an answer that is other than turning this into an equation, then it would be impossible to find an answer. I hope this helped ^^
I think it’s 10,21 and 40, in that order. Sorry if I’m wrong:(
