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3 years ago

Randomly draw a card from a deck of 52 cards. find the probability of drawing a diamond card.

1 answer:

7 0

There are 13 diamonds in the whole deck of cards.
13/52 would be the probability to get a diamond which can further be simplified to 1/4

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Simplify (343) 1/3 a)21 b)19 c)49 d)7

Aliun [14]

I think the answer is D

5 0

3 years ago

A cylindrical oil storage tank has a height of 10 meters and a diameter of 24 meters. If the tank is full, how much oil does it

Fantom [35]

For this case what you should do is find the volume of the tank in the form of a cylinder.
By definition, the volume of a cylinder is:
V = pi * (r ^ 2) * (h)
Where,
h: height
r: radio
Substituting the values we have:
V = 3.14 * ((24/2) ^ 2) * (10)
V = 4521.6 kL
Answer:
If the tank is full, it does contain 4521.6 kL of oil

8 0

3 years ago

The amount of seed a landscaper uses and the area

zepelin [54]

Answer/Step-by-step explanation:

Since there is a proportional relationship between amount of seed a landscaper uses and the area of lawn covered, therefore: constant of proportionality = area covered / seed.

The constant of proportionality would be same for all pairs of values given in the table.

Thus:

$\frac{75}{3} = \frac{25}{1} = 25$

$\frac{100}{4} = \frac{25}{1} = 25$

5 0

3 years ago

A 9m long ladder rests at 9m below a vertical wall. If the angle of elevation of the top of the wall from the foot of the ladder

Arte-miy333 [17]

Height of the wall is 27 m.

Explanation:

Let the height of the wall = h

Length of the ladder = 9 m

Angle of elevation = 60°

Ladder rests at 9 m below a vertical wall.

So, length of the wall upto which the ladder rests = h - 9

We know,

Cos Ф = base/ hypotenuse

cos 60° = length of the ladder / height of wall upto which the ladder rests

$\frac{1}{2} = \frac{9}{h - 9}$

So,

h - 9 = 18

h = 27

Therefore, height of the wall is 27 m

3 0

4 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

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