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pogonyaev
3 years ago
5

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

e area of triangle ABC?
Mathematics
2 answers:
Elena L [17]3 years ago
7 0

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

Naily [24]3 years ago
3 0

Answer:

3

Step-by-step explanation:

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Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave
natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\

So,

AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units

The perimeter of triangle will be:

P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

  • brainly.com/question/573729
  • brainly.com/question/572693

#LearnwithBrainly

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In the figure, OA is a diameter of the smaller circle and O is the centre of the larger circle. Find the
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Answer:

942 6/7 cm²

Step-by-step explanation:

Since O = Center of bigger circle, OA = Radius of bigger circle.

∴ Area of smaller circle - Area of bigger circle = Area of shaded part.

∴ Area of smaller circle = 22/7 × 10²

                                       = 22/7 × 100

                                       = 2200/7

                                       = 314 2/7 cm²

∴ Area of bigger circle = 22/7 × 20 ²

                                      = 22/7 × 400

                                      = 1257  1/7 cm²

∴ Area of shaded part = 1257 1/7 - 314 2/7

                                     =  942 6/7 cm²

5 0
3 years ago
The cost of a car is $15,570. You plan to make a down payment of $1,500, and a monthly payment of $388.08 for 60 months.
sergiy2304 [10]
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