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Ivanshal [37]
3 years ago
13

How could you solve this problem?

Mathematics
2 answers:
Rudiy273 years ago
7 0
I do A and B but that is the way I learned it. Hope this helps :)
Oliga [24]3 years ago
3 0

the first two are the only ones that are true

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Need help please exams tomorrow
Romashka [77]

<u>Answer:</u>

  • The value of x is 14.

<u>Step-by-step explanation:</u>

<u>We know that:</u>

  • ΔABC ≅ ΔEFG
  • 21 x 2/3 = x

<u>Work:</u>

  • 21 x 2/3 = x
  • => 7 x 3 x 2/3 = x
  • => 7 x 2 = x
  • => 14 = x

Hence, <u>the value of x is 14.</u>

Hoped this helped.

7 0
2 years ago
Solve each equation (Isolating first)
Dvinal [7]

3 \times {( \frac{1}{8} )}^{2x}  = 12 \\ \Leftrightarrow {( \frac{1}{8} )}^{2x}  = 4 \\ \Leftrightarrow  {( {2}^{ - 3}) }^{2x}  =  {2}^{2}  \\ \Leftrightarrow  {2}^{ - 6x}  =  {2}^{2}  \\ \Leftrightarrow  - 6x = 2 \\ \Leftrightarrow x =  -  \frac{1}{3}  \\  \\ 2 {\sqrt[3]{5}}^{4x}  = 50 \\ \Leftrightarrow  { \sqrt[3]{5} }^{4x}  = 25 \\ \Leftrightarrow  {5}^{ \frac{4x}{3} }  =  {5}^{2}  \\ \Leftrightarrow  \frac{4x}{3}  = 2 \\ \Leftrightarrow 4x = 6 \\ \Leftrightarrow x =  \frac{3}{2}

7 0
3 years ago
Read 2 more answers
7 trillion divide by 5 is what
IgorLugansk [536]
One trillion four hundred billion
7 0
3 years ago
Find the cosine of angle B.
Alexandra [31]

\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

-

9² = 12² + 15² - 2 (12) (15) cos (B)

81 = 144 + 225 - 360 cos(B)

81 = 369 - 360 cos (B)

360 cos (B) = 369 - 81

360 cos (B) = 288

cos (B) = 0.8

-

Answer: Cosine B = 0.8

-

\boxed { \text {Cosine Rule : } a^2 = b^2 + c^2 - 2bc \cos(A) }

-

12² = 15² + 9² - 2 (15)(9) cos (A)

144 = 225 + 81 - 270 Cos A

144 = 306 - 270 Cos A

270 Cos A = 162

Cos A = 3/5 or 0.6

-

Answer: Cosine Angle A = 3/5

4 0
3 years ago
HHHHHHHHHHHHHHHHHHHHHHHHHHHHEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPP 30 POINTS
Vinvika [58]

Answer:

7.28 units

Step-by-step explanation:

Using the Pythagorean theorem, a^{2} + b^{2} = c^{2}, we get:

2^{2}+7^{2}=c^{2}\\4+49=c^{2}\\53=c^2\\\sqrt{53}=c\\c=\sqrt{53}

\sqrt{53} ≈ 7.28

7 0
3 years ago
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