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Westkost [7]
4 years ago
5

A community is planning to build a rectangular garden.the width of the garden is 27/4 feet and the perimeter of the garden is 37

.5 ft. The community planners want to spread mulch on the entire garden. How many square feet of mulch will be needed.
Help please
Mathematics
1 answer:
Crank4 years ago
7 0

We know that the width of the garden is = \frac{27}{4} feet = 6.75 feet

and Perimeter of the garden is = 37.5 feet

Also, we know that for a rectangular space perimeter = 2 * (l + w)

⇒ 37.5 = 2 * (l + 6.75)

⇒ 37.5 = 13.5 + 2*l

⇒ 24 = 2*l

⇒ l = 12 feet

Now, we need to determine how much square feet of mulch is required, hence we need to calculate the area of the garden

Area = l * w

⇒ Area = 12 * 6.75

⇒ Area = 81 square feet

Hence, they require 81 square feet of mulch

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Answer:

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B. 16i³ = b. -16i

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D. (2i)(8i) = c. -16

Step-by-step explanation:

A. Multiply 2i by 8 to get 16i, which corresponds to d.

B. The exponent is 3 more than a mulitple of 4 in 16i³, so the answer is negative. -16i corresponds to b.

C. (2i)⁴ has an exponent that is a multiple of 4, so the i isn't needed. 16 corresponds to a.

D. (2i)(8i) simplifies to 2(8) * i². The exponent is 2 more than a multiple of 4, so the answer is negative, without an i. -16 corresponds to c.

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To hang lights up on his house.Garrett place is a 14 foot ladder 4 feet from the base of the house. How high up the house will t
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This seems like a right triangle problem.

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Hope this helps!

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3 0
2 years ago
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
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Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

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During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

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3 years ago
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