v = hvh
Simplifying the above equation:
v = h × v × h
Taking the RHS 'v' to LHS
⇒ v ÷ v = h × h
⇒ 1 = h × h
⇒ 1 = 
⇒ h = √1
⇒ h = 
So h can have the values +1 or -1.
Putting h = +1 in the equation,
v = (+1) × v × (+1)
⇒ v = v
Hence, v can take any integer value.
Putting h = -1 in the equation, when h = 1.
v = (-1) × v × (-1)
⇒ v = v
Hence, v can take any integer value when h = -1.
Hence, as long as h is either +1 or -1, v can take any integer value.
Let <em>f</em> and <em>s</em> denote the amounts of the <u>f</u>irst and <u>s</u>econd brands that the chef is going to use.
She wants to end up with 290 mL, so
<em>f</em> + <em>s</em> = 290
Each mL of the first brand contains 0.08 mL of vinegar, and each mL of the second contains 0.13 mL of vinegar. The final mixture should have a concentration of 12% vinegar, so that it contains 0.12 • 290 mL = 34.8 mL of vinegar, and
0.08<em>f</em> + 0.13<em>s</em> = 34.8
Solve for <em>f</em> and <em>s</em> :
<em>f</em> + <em>s</em> = 290 → <em>s</em> = 290 - <em>f</em>
0.08<em>f</em> + 0.13 (290 - <em>f </em>) = 34.8
0.08<em>f</em> + 37.7 - 0.13<em>f</em> = 34.8
0.05<em>f</em> = 2.9
<em>f</em> = 58
<em>s</em> = 290 - 58
<em>s</em> = 232
Answer:
$12 is the price of a ticket
Step-by-step explanation:
happy day ahead
Answer:
(c) (12th root of 8)^x
Step-by-step explanation:
The applicable rules of exponents are ...
![(a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}](https://tex.z-dn.net/?f=%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B1%20%5C%21%20%2Fn%7D)
In this case, we have ...
![(\sqrt[3]{8})^{x/4}=8^{1/3\cdot x/4}=8^{x/12}=\boxed{\left(\!\sqrt[12]{8}\right)^x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B8%7D%29%5E%7Bx%2F4%7D%3D8%5E%7B1%2F3%5Ccdot%20x%2F4%7D%3D8%5E%7Bx%2F12%7D%3D%5Cboxed%7B%5Cleft%28%5C%21%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5Ex%7D)
Answer:
it's 12% goodnight to you
