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ExtremeBDS [4]
3 years ago
11

Rearrange the formula to find the underlined variables.

le="v = hvh" alt="v = hvh" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
qaws [65]3 years ago
5 0

v = hvh

Simplifying the above equation:

v = h × v × h

Taking the RHS 'v' to LHS

⇒ v ÷ v = h × h

⇒ 1 = h × h

⇒ 1 = h^{2}

⇒ h = √1

⇒ h = \left \{ {{h=1} \atop {h=-1}} \right.

So h can have the values +1 or -1.

Putting h = +1 in the equation,

v = (+1) × v × (+1)

⇒ v = v

Hence, v can take any integer value.

Putting h = -1 in the equation, when h = 1.

v = (-1) × v × (-1)

⇒ v = v

Hence, v can take any integer value when h = -1.

Hence, as long as h is either +1 or -1, v can take any integer value.

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