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NeX [460]
3 years ago
5

What is the solution to the following system of equations 4x + 2 = -2y 6y - 18 = 6x

Mathematics
1 answer:
Pavel [41]3 years ago
8 0

Answer:

The solution to the system of equations are;

x = -4/3

y = 5/3

Step-by-step explanation:

To find the Solution, we would carry the Operation simultaneously.

4x + 2 = -2y .........(i)

6y - 18 = 6x ..........(ii)

First let's rearrange the equations, to make the journey smoother

2y + 4x = -2 ...........(iii)

6y - 6x = 18 ...........(iv)

Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.

3.2y + 3.4x = -2 . 3

6y + 12x = -6............... (v)

Let's subtract equation (v) from equation (iv)

= 0y - 18x = 24

-18x = 24

x = - 24 / 18

x = -4/3

Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:

6y - 18 = 6x

6y - 18 = 6 (-4/3)

6y - 18 = -8

6y = -8 + 18

6y = 10.

y = 10 / 6

y = 5/3

The solution to the system of equations are;

x = -4/3

y = 5/3

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25x+75 and there you go.
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Factorize completely <br> 81k^2 - m^2
Genrish500 [490]

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Prove this by FOILing.

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Inner - 9km

Last - (-m^2)

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⭐ Answered by Hyperrspace (Ace) ⭐

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A manufacturer of televisions subjects the equipment to a comprehensive testing process for all essential functions before the t
Vikki [24]

Answer:

The value is   P(X \ge 9) = 0.9138

Step-by-step explanation:

From the question we are told that

  The probability of passing the test is  p =  0.95

  The sample size is  n  =  10  

Generally the distribution of the comprehensive testing of equipment  follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators

  Generally the probability that at least 9 pass the test  is mathematically represented as

    P(X \ge 9) =  P(X = 9 ) + P(X = 10 )

=> P(X \ge 9) =  [^{10}C_9 *  (0.95)^9 *  (1- 0.95)^{10-9}] + [^{10}C_{10} *  (0.95)^{10} *  (1- 0.95)^{10-10}]

=> P(X \ge 9) =  [0.3151] + [0.5987]

=> P(X \ge 9) = 0.9138

7 0
3 years ago
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