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3 years ago

What is the solution to the following system of equations 4x + 2 = -2y 6y - 18 = 6x

Mathematics

1 answer:

Pavel [41]3 years ago

8 0

Answer:

The solution to the system of equations are;

x = -4/3

y = 5/3

Step-by-step explanation:

To find the Solution, we would carry the Operation simultaneously.

4x + 2 = -2y .........(i)

6y - 18 = 6x ..........(ii)

First let's rearrange the equations, to make the journey smoother

2y + 4x = -2 ...........(iii)

6y - 6x = 18 ...........(iv)

Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.

3.2y + 3.4x = -2 . 3

6y + 12x = -6............... (v)

Let's subtract equation (v) from equation (iv)

= 0y - 18x = 24

-18x = 24

x = - 24 / 18

x = -4/3

Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:

6y - 18 = 6x

6y - 18 = 6 (-4/3)

6y - 18 = -8

6y = -8 + 18

6y = 10.

y = 10 / 6

y = 5/3

The solution to the system of equations are;

x = -4/3

y = 5/3

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The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
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=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

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