All categories

2 years ago

Which proportion would you set up to change 6 cups to pints?

Mathematics

2 answers:

Butoxors [25]2 years ago

8 0

The answer is b just do the math and you sould get tamhat

Iteru [2.4K]2 years ago

6 0

Answer:

The answer would be <u>B</u>

Step-by-step explanation:

i hope this helped :)
sorry if im wrong

You might be interested in

I’m confused on this one

Lisa [10]

The angle x is half the sum of the intercepted arcs, PQ and NO.

... (1/2)(65° + 45°) = 55° = x° = m∠PMQ

3 0

3 years ago

The expression −310+13m represents a submarine that began at a depth of 310 feet below sea level and ascended at a rate of 13 fe

GenaCL600 [577]

Answer:

206

Step-by-step explanation:

The formula for this problem would be -310 + 13(8) which = 206

3 0

3 years ago

What is the other square root of 119 + 120i?

MakcuM [25]

Answer:

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

Step-by-step explanation:

Given

z = 119 + 120 i

Let $\sqrt{119+120 i}=p+iq$

Squaring both sides

$119+120 i=p^2-q^2+2ipq$

Comparing real and imaginary part

Re(LHS)=Re(RHS)

$119=p^2-q^2$ ...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

$q=\frac{60}{p}$

Substitute q in 1

$119=p^2-(\frac{60}{p})^2$

$p^4-119p^2-(68)^2=0$

Let $x=p^2$

$x^2-119x-4624=0$

$x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}$

$x=\frac{119\pm 180.71}{2}$

we take only Positive value because $p^2=x$

x=149.85

$p^2=149.85$

thus $p=\pm 12.24$

$q=\pm 4.90$

thus,

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

8 0

3 years ago

25 x (5 - 2) ➗ 5 - 12

joja [24]

Answer: 3

Step-by-step explanation:

25 x (5 - 2) ➗ 5 - 12

Applying the rule of BODMAS

- Solve task in bracket first

25 x (5 - 2) ➗ 5 - 12

= 25 x (3) ➗ 5 - 12

= 75 ➗ 5 - 12

- Solve task of division next

75 ➗ 5 - 12

= 15 - 12

= 3

Thus, the answer is 3

3 0

3 years ago

Read 2 more answers

Please help with this

ArbitrLikvidat [17]

Answer:

$c = 10$

Step-by-step explanation:

This can be solved with Pythagreon Thereom.

${a}^{2} + {b}^{2} = {c}^{2}$

Follow the steps below. A and B are the heaight an base, C is they hypotonuese.

${6}^{2} + {8}^{2} = {c}^{2} \\ 36 + 64 = {c}^{2} \\ 100 = {c}^{2} \\ 10 = c$

7 0

3 years ago