A17=132
27-20=7 and 34-27=7 so they're adding 7 to each term
A17-A4=13 terms between the last one you're given and the one you're trying to find.
13*7=91
91+41=132
Answer:
The corresponding side is JG
Step-by-step explanation:
Given
JGH similar to PMO
Required
Determine the similar side to PM
To do this, we follow the naming convention of both triangle name, since there is no attachment to support the given parameters.
So:
By comparison: The corresponding side is JG
Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.
Since, perimeter is the total length of the outer boundary of the figure. Therefore,
Perimeter of the polygon is


Area of the polygon = Area of Rectangle + Area of Triangle
![=[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]](https://tex.z-dn.net/?f=%3D%5B%2818%29%20%5Ctimes%20%2815%29%5D%20%2B%20%5B%28%5Cfrac%7B1%7D%7B2%7D%29%20%5Ctimes%20%288%29%20%5Ctimes%20%2815%29%5D)
![=270 + [(\frac{8}{2}) \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B%28%5Cfrac%7B8%7D%7B2%7D%29%20%5Ctimes%20%2815%29%5D)
![=270 + [4 \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B4%20%5Ctimes%20%2815%29%5D)


ok Step-by-step explanation: