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tresset_1 [31]
3 years ago
6

(HALP PLS WILL 100% MARK BRAINLIEST!) Sage has $26 and wants to download some songs from a music

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0

Answer:

<h2>≈ 13</h2>

Step-by-step explanation:

First ,we round 1.79 to the nearest whole dollar:

since 7 ≥ 5 then 1.79 rounded to the nearest whole dollar is 2

now ,we can estimate the greatest number she can download:

26/2 = 13

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LM is the diameter of OP. N L *not drawn to scale IfmXLMN = 48° what is mZNLM? A. 24° B. 42° C. 48° D. 66° E. 84​
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Minor arc KL measures 135°. Circle O is shown. Line segments K O and O L are radii. Which is the radian measure of central angle
snow_lady [41]

StartFraction 3 pi Over 4 EndFraction radians

Step-by-step explanation:

Pi radians is equal to 180°

Given the minor arc angles as 135°, change this value to pi radians

180° =π radians

135° = ?

Cross multiply

135° * π radians / 180°

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Light bulbs manufactured at a certain factory have a 3% probability of being defective. What is the probability that 5 out of a
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There is a 3% chance of each light bulb being defective, and we only want 5 of them to be defective. The chance is then:

3\%^5*97\%^{25}

Or this really small number: 1.13474853e-8
5 0
3 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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