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3 years ago

Im new someone please help

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

6 0

Angle 3 and 4 are supplementary angles and create a straight line.

This means when added together they need to equal 180 degrees.

Angle 3 = 180 - angle 4

Angle 3 = 180-40 = 140 degrees.

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What is the volume of the square pyramid with a base of 20mm and height 23mm

anyanavicka [17]

3066.67 mm is the correct volume

5 0

3 years ago

Is y = x +7 a proportinal relationship, if not why?

agasfer [191]

Answer:

it is. Even you change the value of x, the value of y will also change. Since the y-intercept is 7, if we have 0 as our x value, then the y-value will change to 7. Whenever we change the x value, the y value will also change.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Prove that P (P) = (QA ~ Q)] is a tautology.

alekssr [168]

Answer:

The statement $P \leftrightarrow [(\lnot P) \rightarrow (Q \land \lnot Q)]$ is a tautology.

Step-by-step explanation:

A tautology is a formula which is "always true" that is, it is true for every assignment of truth values to its simple components.

To show that this statement is a tautology we are going to use a table of logical equivalences:

$P \leftrightarrow [(\lnot P) \rightarrow (Q \land \lnot Q)] \equiv$

$\equiv (P \land [(\lnot P)\rightarrow (Q \land \lnot Q)]) \lor(\lnot P \land \lnot [(\lnot P)\rightarrow (Q \land \lnot Q)])$ by the logical equivalences involving bi-conditional statements

$\equiv (P \land [\lnot(\lnot P)\lor (Q \land \lnot Q)]) \lor(\lnot P \land \lnot [\lnot(\lnot P)\lor (Q \land \lnot Q)])$ by the logical equivalences involving conditional statements

$\equiv (P \land [P\lor (Q \land \lnot Q)]) \lor(\lnot P \land \lnot [ P\lor (Q \land \lnot Q)])$ by the Double negation law

$\equiv (P \land [P\lor (Q \land \lnot Q)]) \lor(\lnot P \land \lnot P\land \lnot(Q \land \lnot Q))$ by De Morgan's law

$\equiv (P \land [P\lor F]) \lor(\lnot P \land \lnot P\land \lnot(Q \land \lnot Q))$ by the Negation law

$\equiv (P \land [P\lor F]) \lor(\lnot P \land \lnot P\land \lnot Q \lor \lnot(\lnot Q))$ by De Morgan's law

$\equiv (P \land [P\lor F]) \lor(\lnot P \land \lnot P\land \lnot Q \lor Q)$ by the Double negation law

$\equiv (P \land P) \lor(\lnot P \land \lnot P\land \lnot Q \lor Q)$ by the Identity law

$\equiv (P) \lor(\lnot P \land \lnot P\land \lnot Q \lor Q)$ by the Idempotent law

$\equiv (P) \lor(\lnot P \land \lnot P\land (Q\lor \lnot Q))$ by the Commutative law

$\equiv (P) \lor(\lnot P \land \lnot P\land T)$ by the Negation law

$\equiv (P) \lor(\lnot (P \lor P)\land T)$ by De Morgan's law

$\equiv (P) \lor(\lnot (P)\land T)$ by the Idempotent law

$\equiv (P \lor\lnot P) \land(P \lor T)$ by the Distributive law

$\equiv (T) \land(P \lor T)$ by the Negation law

$\equiv (T) \land(T)$ by the Domination law

$\equiv T$

8 0

4 years ago

The monthly starting salaries of students who receive an MBA degree have a population standard deviation of $120. What sample si

mart [117]

Answer:

138

Step-by-step explanation:

Population standard deviation = $\sigma = 120$

.95 probability of estimating the population mean monthly income within a margin of $20

So, Significance level = 1-0.95 = 0.05

α =0.05

Margin error = 20

$ME =Z \times \frac{\sigma}{\sqrt{n}}$

Z at 0.05 = 1.96

$20 =1.96 \times \frac{120}{\sqrt{n}}$

$\sqrt{n} =1.96 \times \frac{120}{20}$

$n =(1.96 \times \frac{120}{20})^2$

$n =138.2976$

So, n = 138

Hence sample size should be 138 selected to obtain a .95 probability of estimating the population mean monthly income within a margin of $20

7 0

3 years ago

Jada uses 7.4 pints of white paint and blue paint to paint her bedroom walls. 4 5 of this amount is white paint, and the rest is

blondinia [14]

Answer:Amount of blue paints used to paint bedroom walls=1.48 pints

Step-by-step explanation:

total pints of white paint and blue paint = 7.4 pints

Amount of white paint=4/ 5 x 7.4 pints=5.92pints

Amount of blue paints used to paint bedroom walls=total pints of paints used -Amount of white paint used

= 7.4 pints-5.92pints

=1.48pints

3 0

3 years ago

Im new someone please help​

Im new someone please help