Prove:
Using mathemetical induction:
P(n) = 
for n=1
P(n) = 
= 6
It is divisible by 2 and 3
Now, for n=k, 
P(k) = 
Assuming P(k) is divisible by 2 and 3:
Now, for n=k+1:
P(k+1) = 
P(k+1) = 
P(k+1) = 
Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also
divisible by 2 and 3.
Hence, by mathematical induction, P(n) = is divisible by 2 and 3 for all positive integer n.
2x^2 + x + 3=0 has only complex roots.
The determinant is 1-4*2*3 = -23
-23 (or any determinant) is the part under the square root sign, If that determinant is negative, knowing you cannot take the square root of a negative number, we know the answers must be complex.
Your answer is 62.5. Hope i helped
Answer: I need a picture off the pool and measurements.
Step-by-step explanation: I need this in order to figure out the problem and give you a helpful answer.
Hello :
f(x) = √(x-3)
answer: B x-3 <span>≥ 0</span>
