x=3 and x= -2
Step-by-step explanation:
we could simplify it to x*2 + x -6 = 0
then 2 numbers whose sum is 1 and product is -6
the numbers are 3 and -2
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
<span>So, what you need to take into consideration here is the order of operations. First, you have to multiply 3 by 6 and then do the rest of the question in the order it is written. So, here is how to calculate this: 3 - 3x6 +2 = 3 - 18 + 2 = -15 + 2 = -13. The correct answer is -13.Hope this helps. Let me know if you need additional help!</span><span />
Answer:
Step-by-step explanation:
Answer:
The points are (1, 1), (2, 3), (3, 5), (4, 7)
